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2 years ago

8

I need help!!! i attached a photo of the math!!

2 answers:

pochemuha2 years ago

8 0

<u>Answer:</u>

<h2>-1/P3</h2><h3>minus 1 P cube</h3>

<u>Step-by-step explanation:</u>

Hope this helps you :)

yKpoI14uk [10]2 years ago

3 0

Answer:-1/p^3

Step-by-step explanation:You do exponents first so -p to the power of -7 is -1/p^7 which then you do -p^4 which is p^4 multiply both you get -1/p^3

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Determine which is the better buy. 7.38 for 2 pounds and 9.57 for 3 pounds.

Amanda [17]

Answer:

Let's find unit price. 7.38 / 2 = 3.69 and 9.57 / 3 = 3.19. Since 3.19 < 3.69 the better buy is 9.57 for 3 pounds.

6 0

2 years ago

Read 2 more answers

Please help with problem 25, part a and b Algebra 1, In the attachment.

erica [24]

The equation to represent the number of people that can attend the event will be 18500 +/- 1200.

<h3>How to calculate the value?</h3>

Based on the information, equation to represent the number of people that can attend the event will be 18500 +/- 1200.

The maximum number will be:

= 18500 + 1200

= 19700

The minimum number will be:

= 18500 - 1200

= 17300

Learn more about equations on:

brainly.com/question/13763238

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4 0

10 months ago

How would you factor 5x²+17x+6=0

labwork [276]

5x^2+17x+6=0
(5x+2)(x+3)=0
5x+2=0 x+3=0
x=-2/5 x=-3
Cheers,Irys

6 0

2 years ago

Directions: Find the indicated trigonometric ratio as a fraction in simplest form. 1. Sin L =

Rainbow [258]

Answer:

$\sin L = 0.60$

$tan\ N = 1.33$

$\cos L = 0.80$

$\sin N = 0.80$

Step-by-step explanation:

Given

See attachment

From the attachment, we have:

$MN = 6$

$LN = 10$

First, we need to calculate length LM,

Using Pythagoras theorem:

$LN^2 = MN^2 + LM^2$

$10^2 = 6^2 + LM^2$

$100 = 36 + LM^2$

Collect Like Terms

$LM^2 = 100 - 36$

$LM^2 = 64$

$LM = 8$

Solving (a): $\sin L$

$\sin L = \frac{Opposite}{Hypotenuse}$

$\sin L = \frac{MN}{LN}$

Substitute values for MN and LN

$\sin L = \frac{6}{10}$

$\sin L = 0.60$

Solving (b): $tan\ N$

$tan\ N = \frac{Opposite}{Adjacent}$

$tan\ N = \frac{LM}{MN}$

Substitute values for LM and MN

$tan\ N = \frac{8}{6}$

$tan\ N = 1.33$

Solving (c): $\cos L$

$\cos L = \frac{Adjacent}{Hypotenuse}$

$\cos L = \frac{LM}{LN}$

Substitute values for LN and LM

$\cos L = \frac{8}{10}$

$\cos L = 0.80$

Solving (d): $\sin N$

$\sin N = \frac{Opposite}{Hypotenuse}$

$\sin N = \frac{LM}{LN}$

Substitute values for LM and LN

$\sin N = \frac{8}{10}$

$\sin N = 0.80$

7 0

2 years ago

Raj weighs a book and rounds the weights to the nearest tenth. Does this weight round to 1.5 pounds?

Archy [21]

Answer:

Its false

Step-by-step explanation:

4.42 the .42 the 2 is under 5 so it would round up.

7 0

2 years ago