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kirza4 [7]
2 years ago
11

0=>p-10 what does this mean

Mathematics
1 answer:
Bad White [126]2 years ago
6 0
Look it up I don’t know
You might be interested in
Given the equation 2 Square root of x minus 5 = 2, solve for x and identify if it is an extraneous solution.
Luba_88 [7]
Given: 2<span>√(x - 5) = 2

Taking the square of both sides:

 [</span>2√(x - 5) = 2]^2

4(x - 5) = 4
x - 5 = 1
x = 6

Among the choices, the correct answer is A. <span>x = 6, solution is not extraneous .</span>
3 0
4 years ago
Read 2 more answers
What is 5-(-27-(-189+243x)) distributed
maw [93]
Sorry if this is wrong and it doesn't hep but I got 32
7 0
3 years ago
Plz help i will mark brainlest if correct
velikii [3]

We should get extra points for decoding the question.  Is that computer generated?

It's easier for us if you type it in using math symbols, with lots of parentheses for clarity, or just post a photo.

If

(-3)^{-5} = \dfrac{1}{x}

what is the value of x?

That's straightforward:

x = \dfrac{1} {(-3)^{-5}} = (-3)^5 = -243

Answer: -243

5 0
4 years ago
Read 2 more answers
A set S of strings of characters is defined recursively by 1. a and b belong to S. 2. If x belongs to S, so does xb. Which of th
alukav5142 [94]

Answer:

a) a

b) ab

e) bbbbb

Step-by-step explanation:

We are given the following in the question:

a, b \in S

x \in S \Rightarrow xb \in S

a) a

It is given that a \in S

b) ab

\text{If }a \in S\\\Rightarrow ab \in S

Thus, ab belongs to S.

c) aba

This does not belong to S because we cannot find x for which xb belongs to S.

d) aaab

This does not belong to S because we cannot find x for which xb belongs to S.

e) bbbbb

\text{If }b \in S\Rightarrow bb \in S\\\text{If }bb \in S\Rightarrow bbb \in S\\\text{If }bbb \in S\Rightarrow bbbb \in S\\\text{If }bbbb \in S\Rightarrow bbbbb \in S

Thus, bbbbb belongs to S.

8 0
3 years ago
Find the value of 1×4+2×5+3×6......n×(n+3)​
Arada [10]

Answer:

n(n+1)(n+5)/3

Step-by-step explanation:

there is no value, as we don't know n.

but we can create a summary formula/ function definition :

this is the sum for k = 1 to n of k×(k+3)

k×(k+3) = k² + 3k

so, the overall sum splits into the sum of k² for k=1 to n, and the sum of 3k for k=1 to n.

and the sum of 3k is 3 times the sum of k for k=1 to n.

Σk² for k=1 to n = [n(n+1)(2n+1)]/6

Σk for k=1 to n = n(n+1)/2

3×Σk for k=1 to n = 3×n(n+1)/2

so, we have a function formula

n(n+1)(2n+1)/6 + 3n(n+1)/2 = n(n+1)(2n+1)/6 + 9n(n+1)/6 =

= n(n+1)(2n+1+9)/6 = n(n+1)(2n+10)/6 = n(n+1)(n+5)/3

3 0
3 years ago
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