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Ivanshal [37]
3 years ago
12

PLZ HURRY Find 64% of 25. Use a fraction.

Mathematics
1 answer:
Monica [59]3 years ago
8 0

25 \times 64\% = 16

64% if 25 is 16.

16 =  \frac{16}{1}


I hope that helps!!
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Find the volume of a sphere and radius is 3. please answer in terms of pi
Ghella [55]

Answer:

12 pi

Step-by-step explanation:

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12 pi unit square

6 0
3 years ago
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The sum of two polynomials is 10a2b2 – 8a2b 6ab2 – 4ab 2. if one addend is –5a2b2 12a2b – 5, what is the other addend? 15a2b2 –
Brrunno [24]

The other polynomial addend, when the sum of two polynomials is 10a2b2 – 8a2b 6ab2 – 4ab  is 15a²b²- 20a²b + 6ab² - 4ab + 7.

<h3>What is polynomial?</h3>

Polynomial equations is the expression in which the highest power of the unknown variable is n (n is real number).

The sum of two polynomials is,

10a^2b^2 - 8a^2b+ 6ab^2 - 4ab+2

The one polynomial addend is,

-5a^2b^2 +12a^2b - 5

Let suppose the other polynomial addend is f(a,b). Thus,

(-5a^2b^2 +12a^2b - 5)+f(a,b)=(10a^2b^2 - 8a^2b+ 6ab^2 - 4ab+2)

Isolate the second polynomial as,

f(a,b)=(10a^2b^2 - 8a^2b+ 6ab^2 - 4ab+2)-(-5a^2b^2 +12a^2b - 5)\\f(a,b)=10a^2b^2 - 8a^2b+ 6ab^2 - 4ab+2+5a^2b^2 -12a^2b + 5

Arrange the like terms as,

f(a,b)=10a^2b^2+5a^2b^2 - 8a^2b -12a^2b+ 6ab^2 - 4ab + 2+5\\f(a,b)=15a^2b^2- 20a^2b + 6ab^2 - 4ab + 7

Hence, the other polynomial addend, when the sum of two polynomials is 10a2b2 – 8a2b 6ab2 – 4ab  is 15a²b²- 20a²b + 6ab² - 4ab + 7.

Learn more about polynomial here;

brainly.com/question/24380382

7 0
2 years ago
70% of the world's snake species lay eggs, while the remaining ones give birth to live young. If there are 2,700 different speci
igomit [66]
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8 0
3 years ago
What is the<br> product of 2/3<br> and 4/5?
Paul [167]
Well, product means multiply so we need to multiply these fractions.

2        4      
--- x ---  =  
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8 0
4 years ago
Read 2 more answers
The City Sights tour company had the same ratio of tourists to guides on both days this weekend. On Saturday, there were 120 tou
Anastasy [175]

Answer:

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5 0
3 years ago
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