We will call an adult ticket <em>a</em>, and a child ticket <em>c</em>.
Since they sold 60 tickets in total, we can form the equation:
a + c = 60
We can also say that the sum of money from the adult tickets and child tickets combined is 460.
Thus we can say
11a + 6c = 460
Now, we must solve our system.
a + c = 60
11a + 6c = 460
6a + 6c = 360
11a + 6c = 460
-5a = -100
a = 20
Thus, (20) + c = 60
c = 40
a = 20 and c = 40
Answer:
Step-by-step explanation:
Answer:
Ehhh
Step-by-step explanation:
Answer: "Count 2 and then count 31 more."
Step-by-step explanation:
We have the equation:
231 - 198
Now, the negative number is kinda ugly, so i will write it as:
200 - 2 = 198
Is a lot easier work with 200 and 2, than with 198.
Then the equation is now:
231 - (200 - 2)
And the left number we also have a "200", so it can be written as:
200 + 31 = 231
As this is a sum, we can ignore the parentheses.
200 + 31 - 200 + 2
31 + 2
Then the correct option is:
"Count 2 and then count 31 more."
Answer:
48
Step-by-step explanation:
