For this case we have the following functions:

When composing the functions we have:

Substituting values we have:

Rewriting:

The function has a horizontal asymptote at y = 3.
Therefore, the range of the function is all reals minus y = 3.
Answer:
option 3
Answer:


<em>Radius: 5</em>
<em>Radius: </em>
Step-by-step explanation:
(see images below)
Hope this helped!
~<u>rere</u>
G(x) would have a translation of 5 to the left, while h(x) would have a translation of 5 up
Answer:
379.94 mi²
Step-by-step explanation:
The area of a circle can be figured out with this formula: πr² (3.14 is π here, as it says in the directions).
We know the diameter is 22 miles. Divide that by 2 to get a radius of 11 miles.
The equation now becomes
3.14(11²)
11 squared is 121.
3.14(121)
I recommend splitting the 121 into 100, 20, and 1.
(3.14 * 100) + (3.14 * 20) + (3.14 * 1)
Multiply 3.14 by 100, 20, and 1.
314 + 62.8 + 3.14
Add 314 and 62.8.
376.8 + 3.14
Add 376.8 and 3.14
379.94 mi² is the area of a circle with a 22-mile diameter.