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2 years ago

15

Hank the savings account in June of 2002 on June 2006 and $3,800 on June 2014 he had $8,600 if hanks saving is modeled by linear

function what was his initial deposit

1 answer:

beks73 [17]2 years ago

5 0

12400 is the answer. Have a good day

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75% of what number is 42?

Anna35 [415]

75 42
----- -----
100 x

75 x= 4200
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75 75

x = 56

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3 years ago

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Kim bought four bottles of water and 2 candy bars at a snack shack. Steve bought one bottle of water and 7 candy bars from the s

OverLord2011 [107]

Answer:A

Step-by-step explanation:

1 bottle is 1.50

4*1.50=5

5+1.25= the total

5divided by 7=0.70

Double check your work I’m not sure if I’m right!

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2 years ago

Jerald jumped from a bungee tower. If the equation that models his height, in feet, is h = –16t2 + 729, where t is the time in s

vekshin1

104 = -16T2 + 729

16t^2 = 729 - 104 = 625

4t = +/-25

t = +/-6.25

Between 6.25 and 13.5 seconds after he jumps

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3 years ago

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1 and 2 are vertical angles. If the<br> measure of 22 is 105°, find the measure of

sergey [27]

If i am not wrong the question of this woyld be the measure of 1 right . Because both of these are vertical angle so they are equal to each other “><“ like that so measure of 1 is 105 tô

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2 years ago

Identify a sequence of transformations that maps triangle ABC onto triangle A"B"C" in the image below.

Murljashka [212]

Answer:

The correct option is B.

Step-by-step explanation:

It is given that triangle A"B"C" is the image of triangle ABC after transformation.

From the given figure it is noticed that the point C lies on positive y-axis and point C" lies on negative x-axis.

It means the figure is rotated either counterclockwise 90° or clockwise 270°. The rotation rule is

$(x,y)\rightarrow (-y,x)$

The corresponding sides of image A"B"C" are smaller than the preimage ABC.

$k=\frac{A"B"}{AB}=\frac{3}{6}=\frac{1}{2}$

Since k<0, therefore the transformation shows the reduction. The dilation rule is

$(x,y)\rightarrow (-\frac{1}{2}y,\frac{1}{2}x)$

$A(-3,0)\rightarrow (-\frac{1}{2}(0),\frac{1}{2}(-3))\rightarrow (0,-1.5)$

$B(3,0)\rightarrow (-\frac{1}{2}(0),\frac{1}{2}(3))\rightarrow (0,1.5)$

$C(0,5.2)\rightarrow (-\frac{1}{2}(5.2),\frac{1}{2}(0))\rightarrow (-2.6,0)$

Option B is correct.

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2 years ago

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