Question

How do I find out 4)?

Answer 1

Answer:

Step-by-step explanation:

Given expression is,

$\lim_{m \to \infty} \frac{4m^2-6m+1}{3m^2+5m+7}$

By dividing denominator and numerator of the given fraction by m²,

$\lim_{m \to \infty} \frac{\frac{4m^2-6m+1}{m^2} }{\frac{3m^2+5m+7}{m^2} }$

= $\lim_{m \to \infty} \frac{4-\frac{6}{m} +\frac{1}{m^2} }{3+\frac{5}{m} +\frac{7}{m^2} }$

We know that $\lim_{n \to \infty} \frac{1}{n}=0$

$\lim_{m \to \infty} \frac{4-\frac{6}{m} +\frac{1}{m^2} }{3+\frac{5}{m} +\frac{7}{m^2} }=\frac{4-0+0}{3+0+0}$

                            $=\frac{4}{3}$

Therefore, We can evaluate the limit of the expression by substituting ∞ in for m.