Answer:
Answer: Program to estimate the power spectral density of the signal
Explanation:
fs= 4000; % Hz sample rate Ts= 1/fs; f0= 500; % Hz sine frequency A= sqrt(2); % V sine amplitude for P= 1 W into 1 ohm. N= 1024; % number of time samples n= 0:N-1; % time index x= A*sin(2*pi*f0*n*Ts) + .1*randn(1,N); % 1 W sinewave + noise
Spectrum in dBW/Hz
nfft= N; window= rectwin(nfft); [pxx,f]= pwelch(x,window,0,nfft,fs); % W/Hz power spectral density PdB_Hz= 10*log10(pxx); % dBW/Hz
Spectrum in dBW/bin
nfft= N; window= rectwin(nfft); [pxx,f]= pwelch(x,window,0,nfft,fs); % W/Hz power spectral density PdB_bin= 10*log10(pxx*fs/nfft); % dBW/bin
C, because technology has changed our social life by texting and messaging.
Hope this helps
Answer:
umm
Explanation:
i don't think this is the question look at your wording
Answer:
24.167 micro seconds.
Explanation:
The given rotation rate = 7200 rpm = 7200 rounds per minute
Rotational latency is the average time taken for the head to reach starting of sector
.
Rotational latency (in micro seconds) = (1 / (RPM / 60)) * 0.5 * 1000
(1/(7200/60))* 0.5 * 1000 = 4.167 ms
Thus, rotational latency = 4.167 ms.
Seek time = 20 ms
The average time taken for the access head to get to the beginning of randomly selected sector will be equal to the average time to first reach the random track plus the average time taken to reach random sector
.
= 20 ms + 4.167 ms = 24.167 micro seconds.
Thus, it would take 24.167 micro seconds to get the access head to the beginning of a randomly selected sector on a randomly selected track.
