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timurjin [86]
4 years ago
13

A(n) _________________________ is a character that word displays on the screen but is not visible on a printed document.

Computers and Technology
1 answer:
oksano4ka [1.4K]4 years ago
6 0
Nonprint ...but im like 99 percent sure
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bija089 [108]

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More potential energy was stored and released as kinetic energy in the balloon that went farther.

Explanation:

I'm taking the test ; )

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The color gradient is
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A range of position dependent colors
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Which table option automatically adjusts column widths to fit cell content? autofit contents merge cells autofit window fixed co
noname [10]
Which table option automatically adjusts column widths to fit cell content?
autofit contents
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3 years ago
Plsss help me<br>give two examples of problems that can occur when sytems do not work properly​
melomori [17]

Answer:

Explanation:

1. There can be a run out of something ex. The water cycle we could run out of water if evaporation stops happening

2. Something wont happen ex. In a shoe factory if no one is boxing the shoes the shoes don’t get boxed.

Hope this helps

6 0
3 years ago
Given parameters b and h which stand for the base and the height of an isosceles triangle (i.e., a triangle that has two equal s
schepotkina [342]

Answer:

The area of the triangle is calculated as thus:

Area = 0.5 * b * h

To calculate the perimeter of the triangle, the measurement of the slant height has to be derived;

Let s represent the slant height;

Dividing the triangle into 2 gives a right angled triangle;

The slant height, s is calculated using Pythagoras theorem as thus

s = \sqrt{b^2 + h^2}

The perimeter of the triangle is then calculated as thus;

Perimeter = s + s + b

Perimeter = \sqrt{b^2 + h^2} + \sqrt{b^2 + h^2} +b

Perimeter = 2\sqrt{b^2 + h^2} + b

For the volume of the cone,

when the triangle is spin, the base of the triangle forms the diameter of the cone;

Volume = \frac{1}{3} \pi * r^2 * h

Where r = \frac{1}{2} * diameter

So, r = \frac{1}{2}b

So, Volume = \frac{1}{3} \pi * (\frac{b}{2})^2 * h

Base on the above illustrations, the program is as follows;

#include<iostream>

#include<cmath>

using namespace std;

void CalcArea(double b, double h)

{

//Calculate Area

double Area = 0.5 * b * h;

//Print Area

cout<<"Area = "<<Area<<endl;

}

void CalcPerimeter(double b, double h)

{

//Calculate Perimeter

double Perimeter = 2 * sqrt(pow(h,2)+pow((0.5 * b),2)) + b;

//Print Perimeter

cout<<"Perimeter = "<<Perimeter<<endl;

}

void CalcVolume(double b, double h)

{

//Calculate Volume

double Volume = (1.0/3.0) * (22.0/7.0) * pow((0.5 * b),2) * h;

//Print Volume

cout<<"Volume = "<<Volume<<endl;

}

int main()

{

double b, h;

//Prompt User for input

cout<<"Base: ";

cin>>b;

cout<<"Height: ";

cin>>h;

//Call CalcVolume function

CalcVolume(b,h);

//Call CalcArea function

CalcArea(b,h);

//Call CalcPerimeter function

CalcPerimeter(b,h);

 

return 0;

}

3 0
3 years ago
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