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yan [13]
2 years ago
13

1.3.3 The cube root of 27​

Mathematics
1 answer:
myrzilka [38]2 years ago
7 0

Answer:

The cube root of 27 is 3.

Step-by-step explanation:

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Answer:

Step-by-step explanation: For part 1, it makes sense that the form is y = m + c. So, it is a simply rearrangement of the equation to start with, in order to make  the subject. This is the graph in slope-intercept form. From here it is easy to see that gradient  = and the y-intercept = 490. The easiest way to draw a straight-line graph, such as this one, is to plot the y-intercept, in this case (0, 490), then plot another point either side of it at a fair distance (for example substitute  = -5 and  = 5 to procure two more sets of co-ordinates). These can be joined up with a straight line to form a section of the graph, which would otherwise extend infinitely either side - use the specified range in the question for x-values, and do not exceed it (clearly here the limit of -values is 0 ≤ x ≤ 735, since neither x nor y can be negative within the context of the question - the upper limit was found by substituting  = 0). In easy terms, the graph of this function represents how the value of the function varies as the value of x varies. Looking back at the question context, this graph specifically represents how many wraps could have been sold at each number of sandwich sales, in order to maintain the same profit of $1470. When the profit is higher, the gradient is not changed (this is defined by the relationship between the $2 and $3 prices, not the overall profit) - instead the -intercept is higher, therefore we have gleaned that the new y-intercept is 531. Clearly I cannot see the third straight line. However the method for finding the equation of a straight line graph is fairly simple:

1. Select two points on the line and write down their coordinates

2. The gradient of the line =

3. Find the change in  (Δ

4. Find the change in  (Δ

5. Divide the result of stage 3 by the result of stage 4

6. This is your gradient

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8. There is only one variable left, which is  (the y-intercept). Simply solve for this

9. Now generalise the equation, in the form , by inputting your gradient and y-intercept whilst leaving the coordinates as  and

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Δ = 6 - 9 = -3

Δ = 4 - 1 = 3

=  = -1

I choose the point (4, 6)

6 = (-1 * 4) + c

6 = c - 4

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