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horsena [70]
3 years ago
14

What is the measure of EGF? What is the measure of CGF?

Mathematics
1 answer:
noname [10]3 years ago
8 0

Answer:

65 degree, 15 degree

Step-by-step explanation:

In triangle GEF,

∠E = ∠G (Given)

Let's say,

∠E = ∠G = x

∠E + ∠G + ∠F = 180 (Angle sum property of Triangle)

=>x + x + ∠F = 180

=>2x + ∠F = 180

=>2x + 50 = 180

=>2x = 180-50

=> 2x =130

=> x = 130/2

=> x = 65

=>∠E = ∠G = 65

=>∠GEF = ∠EGF = 65 Degree

∠EGF + ∠CGF = 180

=>65 + ∠CGF =180

=>∠CGF = 180 - 65

=> ∠CGF = 15

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Vedmedyk [2.9K]
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parallel lines  has same slope = -1/2
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if slope not equal either -1/2 or 2 then neither.

y = -1/2 x - 5 ....m= - 1/2....  parallel

-2x + y = -4
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2y = x + 2
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3 years ago
Read 2 more answers
The measurenicnt of the circumference of a circle is found to be 56 centimeters. The possible error in measuring the circumferen
BartSMP [9]

Answer:

(a) Approximate the percent error in computing the area of the circle: 4.5%

(b) Estimate the maximum allowable percent error in measuring the circumference if the error in computing the area cannot exceed 3%: 0.6 cm

Step-by-step explanation:

(a)

First we need to calculate the radius from the circumference:

c=2\pi r\\r=\frac{c}{2\pi } \\c=8.9 cm

I leave only one decimal as we need to keep significative figures

Now we proceed to calculate the error for the radius:

\Delta r=\frac{dt}{dc} \Delta c\\\\\frac{dt}{dc} =    \frac{1}{2 \pi } \\\\\Delta r=\frac{1}{2 \pi } (1.2)\\\\\Delta r= 0.2 cm

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Again only one decimal because the significative figures

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A=\pi r^{2}\\A=249 cm^{2}

Then we calculate the error:

\Delta A= (\frac{dA}{dr} ) \Delta r\\\\\Delta A= 2\pi r \Delta r\\\\\Delta A= 11.2 cm^{2}

A=249 \pm 11.2 cm^{2}

Now we proceed to calculate the percent error:

\%e =\frac{\Delta A}{A} *100\\\\\%e =\frac{11.2}{249} *100\\\\\%e =4.5\%

(b)

With the previous values and equations, now we set our error in 3%, so we just go back changing the values:

\%e =\frac{\Delta A}{A} *100\\\\3\%=\frac{\Delta A}{249} *100\\\\\Delta A =7.5 cm^{2}

Now we calculate the error for the radius:

\Delta r= \frac{\Delta A}{2 \pi r}\\\\\Delta r= \frac{7.5}{2 \pi 8.9}\\\\\Delta r= 0.1 cm

Now we proceed with the error for the circumference:

\Delta c= \frac{\Delta r}{\frac{1}{2\pi }} = 2\pi \Delta r\\\\\Delta c= 2\pi 0.1\\\\\Delta c= 0.6 cm

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