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svet-max [94.6K]
3 years ago
15

What is the determinant of Hasap ​

Mathematics
1 answer:
dalvyx [7]3 years ago
3 0

Answer:

H = 15

Step-by-step explanation:

If you need an explnation, I can provide it if needed! Cheers!

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Calculate the area of the shaded region between the regular polygons. Round to the nearest hundredth.
wolverine [178]

Answer:

I hope I'll help you with this but I am not sure of it all...

The area of the shaded region is 46,77

Step-by-step explanation:

To determine the area of the shaded hexagon, we must first calculate te area of the whole shaded hexagon and minus that by the white little hexagon.

The formula to calculate the area of a hexagon is (3√3 s2)/ 2

(where s = one side of the hexagon)

if one side a the little white hexagon equals 6 ft;

3√3 6ft.2/2 = 18√3/2 = 9√3

now for the bigger hexagon where one side is 12 ft;

3√3 12 ft.2/2 = 72√3/2 = 36√3

now the area of the bigger one minus the area of the smaller one;

36√3 - 9√3 = 46,77

3 0
2 years ago
Given the functions, f(x) = x2 + 2 and g(x) = 4x - 1, perform the indicated operation. When applicable, state the domain restric
Naya [18.7K]

Answer:

3rd option

Step-by-step explanation:

substitute x = f(x) into g(x)

g(f(x))

= g(x² + 2)

= 4(x² + 2) - 1

= 4x² + 8 - 1

= 4x² + 7

5 0
2 years ago
Find the surface area of the prism.
joja [24]
Multiply it && get your answer the fraction is 1.20
4 0
3 years ago
If a(b+c)=d and a, b, c and d are all integer, then which of the following must be true?
lions [1.4K]

Answer:

B. ab+ac=d

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
Prove that sin20sin40sin60sin80=3/16
never [62]
We'll use the following properties of sine and cosine to prove this:

sin(a)\cdot sin(b) = \frac12(cos(a-b) - cos(a+b))

cos(a)\cdot cos(b) = \frac12(cos(a+b) + cos(a-b))

cos(180+a) = cos(180-a)

Then it's just a matter of filling it in...

sin20sin40 * sin60sin80 = 1/2(cos20 - cos60) * 1/2 (cos20 - cos140) =

1/8( cos40 + 1 - cos160 - cos120 - cos40 - cos80 + cos80 + cos200) =

1/8(1 -  cos160 - cos120 + cos200) =

1/8(1 -  cos160 - cos120 + cos160) =

1/8(1 - cos120 ) = 1/8( 1 + 1/2 ) = 3/16

5 0
3 years ago
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