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3 years ago

Select the correct answer.

Mathematics

2 answers:

Papessa [141]3 years ago

6 0

Answer:

the equation is y = 11x - 7

B is the answer

torisob [31]3 years ago

3 0

The answer is B
y=11x-7

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Una expresion equivalente a <br> 2(2x+11)-(-5+3x)

nordsb [41]

Answer:

x+27

Step-by-step explanation:

2(2x+11)-(-5+3x)

Distribute

4x +22 +5-3x

Combine like terms

x+27

5 0

3 years ago

Read 2 more answers

Which expression is equivalent to 6–3?

Bond [772]

Your question is not well presented. See complete question below

Which expression is equivalent to $6^{-3}$ ?

A) –63

B) 36

C) $\sqrt[3]{6}$

D) $(\frac{1}{6} )^3$

Answer:

The equivalent of $6^{-3$ is $(\frac{1}{6} )^3$

Step-by-step explanation:

Given

Expression: $6^{-3}$

Required:

Find the Equivalent Expression

To find the equivalent of this expression, we make use of law of indices.

One of the laws of indices states that

$a^-b = \frac{1}{a^b}$

If we apply this law to the expression above ( $6^{-3}$ )

By comparison a = 6 and b = 3.

So, $6^{-3}$ becomes

$6^{-3}$ = $\frac{1}{6^3}$

Simplifying further;

$\frac{1}{6^3}$ = $\frac{1}{6 * 6 * 6}$

This can also be written as

$\frac{1}{6^3}$ = $\frac{1*1*1}{6 * 6 * 6}$

By splitting the above expression; we have that

$\frac{1}{6^3}$ = $\frac{1}{6} * \frac{1}{6} * \frac{1}{6}$

Multiplication law of indices states that;

a * a * a = a³. (Because they have the same base of a)

So, $\frac{1}{6} * \frac{1}{6} * \frac{1}{6}$ can then be written as $(\frac{1}{6} )^3$

Hence, $\frac{1}{6^3}$ = $(\frac{1}{6} )^3$

So, the equivalent of $6^{-3}$ is $(\frac{1}{6} )^3$

7 0

3 years ago

I literally just want someone to write a standard form equation for like graphs and stuff, I need to see the difference between

pav-90 [236]

Point slope form: y-y-coordinate=slope(x-x-coordinate)
slope intercept form: y=mx+b
standard form: x + y=

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3 years ago

Chuck must save a total of 180 for a new bike. So far he has saved 4/5 of the amount. How much money has chuck saved for the bik

4vir4ik [10]

He has saved $144 out of $180

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3 years ago

A city’s population, P, is modeled by the function P(x) = 78,500( 1.02 )x where x represents the number of years after the year

serg [7]

I presume this is meant to be exponential.

When f(x) = a(b)^x, a represents the starting value, b represents change, and x represents time.

The population began in 2000 (x = 0). This makes the equation equal to 78,500, which is your starting value and population in 2000.

1.02 means that the initial value is multiplied by 1.02 or 102% each year. Therefore, there is a 2% increase.

6 0

4 years ago