Answer:
50
Step-by-step explanation:
I'm sorry but your missing the questions but I found a close answer! Let A be the number of cards Alan has B be the number of cards Bill has C be the number of cards Calvin has Alan had 11 less than 2 1/2 times the number of cards bill has. is 2.5 Alan is 2.5 of bill has minus 11 A=2.5B -11 Calvin has 1 more than 1 1/2 times the number of cards bill has. is 1.5 Calvin is 1.5 of bill has plus 1 C=1.5B + 1 Alan and Calvin have the same number of cards So A=C WE plug in A and C equations and solve for B 2.5B -11 = 1.5B + 1 (subtract 1.5B on both sides) 1B -11 = 1 (Add 11 on both sides) B = 12 If Alan and Calvin have the same number of cards, the number bill has is 12 The number of cards Alan and Calvin each have is 19 Total cards = 12 + 19 + 19 = 50 If Alan, bill, and Calvin have all the cards in the deck then the deck has 50 cards.
Answer:
(-8, 135°)
Step-by-step explanation:
(8, -45°) has magnitude 8 and direction -45°.
If we add 180° to the direction and change the sign of the magnitude, we'll have the same point.
(-8, -45° + 180°) = (-8, 135°)
A) The probability the golfer got zero or one hole-in-one during a single game is between 10.01% and 11.38%.
B) The probability the golfer got exactly two holes-in-one during a single game is 8.57%.
C) The probability the golfer got six holes-in-one during a single game is close to 0%.
<h2 /><h2><u>How to determine probabilities</u></h2>
Since a miniature golf player sinks a hole-in-one about 12% of the time on any given hole and is going to play 8 games at 18 holes each, to determine A) what is the probability the golfer got zero or one hole -in-one during a single game, B) what is the probability the golfer got exactly two holes-in-one during a single game, and C) what is the probability the golfer got six holes-in-one during a single game , the following calculations must be performed:
- 1 - 0.12 = 0.88
- 0.88 ^ 17 = 0.1138
- 0.88 ^ 18 = 0.1001
Therefore, the probability the golfer got zero or one hole-in-one during a single game is between 10.01% and 11.38%.
- 0.88 ^ 18 - 0.12 ^ 2 = X
- 0.0857 = X
Therefore, the probability the golfer got exactly two holes-in-one during a single game is 8.57%.
- 0.12 ^ 6 x 0.88 ^ 12 = X
- 0.0000000001 = X
Therefore, the probability the golfer got six holes-in-one during a single game is close to 0%.
Learn more about probabilities in brainly.com/question/25273534
Answer:
The margin of error for the 95% confidence interval for the mean score of all such subjects is of 8.45.
Step-by-step explanation:
We have the standard deviation for the sample, which means that the t-distribution is used to solve this question.
The first step to solve this problem is finding how many degrees of freedom, we have. This is the sample size subtracted by 1. So
df = 27 - 1 = 26
95% confidence interval
Now, we have to find a value of T, which is found looking at the t table, with 26 degrees of freedom(y-axis) and a confidence level of
. So we have T = 2.0518
The margin of error is:

In which s is the standard deviation of the sample and n is the size of the sample.
In this question:
. So


The margin of error for the 95% confidence interval for the mean score of all such subjects is of 8.45.
In an equation the Left hand side must equal the right hand side
4(5y-8-2)=185-15
20y-32-8=170
20y=170+32+8
20y=210
Therefore y=10,5
When you substitute the 10,5 and solve it on the left and side it's equal to 170 which is the answer on the right hand side