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2 years ago

Click on the pic and pls help!!

Mathematics

1 answer:

Natasha_Volkova [10]2 years ago

6 0

Answer:

x = 43.9

Step-by-step explanation:

sin 20° = 15/x

0.3420 = 15/x

x = 43.86

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What is the mean of Variable A?

Pachacha [2.7K]

5 is the mean of variable a I might be wrong

8 0

2 years ago

Find the exact value of cos theta, given that sin thetaequalsStartFraction 15 Over 17 EndFraction and theta is in quadrant II.

vova2212 [387]

Answer:

$cos \theta = -\frac{8}{17}$

Step-by-step explanation:

For this case we know that:

$sin \theta = \frac{15}{17}$

And we want to find the value for $cos \theta$ , so then we can use the following basic identity:

$cos^2 \theta + sin^2 \theta =1$

And if we solve for $cos \theta$ we got:

$cos^2 \theta = 1- sin^2 \theta$

$cos \theta =\pm \sqrt{1-sin^2 \theta}$

And if we replace the value given we got:

$cos \theta =\pm \sqrt{1- (\frac{15}{17})^2}=\sqrt{\frac{64}{289}}=\frac{\sqrt{64}}{\sqrt{289}}=\frac{8}{17}$

For our case we know that the angle is on the II quadrant, and on this quadrant we know that the sine is positive but the cosine is negative so then the correct answer for this case would be:

$cos \theta = -\frac{8}{17}$

5 0

2 years ago

Help me please Help me please Help me please Help me please Help me please Help me please Help me please Help me please Help me

levacccp [35]

Answer:

5 units

Step-by-step explanation:

You can use the distance formula or pythagorean theorem to solve this.

Original point A: (0,0)

New point B: (3, 4)

Distance formula: $\sqrt{(x_{2}-x_{1})^{2} +(y_{2}-y_{1})^{2} }$

Plug the points in:

$\sqrt{(3-0)^{2} +(4-0)^{2} }$ = 5

5 units

5 0

2 years ago

Help me again please ‘,:)

cluponka [151]

Answer:

the third or fourth one probably

Step-by-step explanation:

4 0

2 years ago

I need the answer of this with steps and solutions fast plz

Natali [406]

Answer:

$1 \dfrac{13}{15}$

Step-by-step explanation:

$2 \dfrac{1}{5} - \dfrac{1}{3} =$

$= \dfrac{11}{5} - \dfrac{1}{3}$

$= \dfrac{33}{15} - \dfrac{5}{15}$

$= \dfrac{28}{15}$

$= 1 \dfrac{13}{15}$

6 0

2 years ago