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MakcuM [25]
3 years ago
7

An open box is made from a 30​-cm by 70​-cm piece of tin by cutting a square from each corner and folding up the edges. The area

of the resulting base is 1536 cm2. What is the length of the sides of the​ squares?
Mathematics
1 answer:
Llana [10]3 years ago
8 0

Answer:

Give me brainliest and i will do it

Step-by-step explanation:

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What is 20 divided by 10 plus 50
Deffense [45]

Answer:

20/10 + 50=52

Step-by-step explanation:

7 0
3 years ago
If abcd is dilated by a factor of 3, the coordinate of a would be?
Mekhanik [1.2K]
Vvvgggggggggggghgghv
6 0
1 year ago
What is a simpler form of the radical expression?<br><br> SOMEONE PLEASE HELP!!
Brilliant_brown [7]

Answer:

Choice B

Step-by-step explanation:

Given radical expression:

\sqrt[4]{1296 {x}^{16}  {y}^{12} }

To Find:

The Simpler form of this expression

Soln:

=  \sqrt[4]{1296 {x}^{16}  {y}^{12} }

We could re-write the given expression, according to the law of exponents:

=  \tt \sqrt[4]{(6x {}^{4}y {}^{3})  {}^{4}  }

Now we need to bring terms out of the radical as:

\tt =   | 6x { }^{4} y {}^{3}  |

Bring out 6x^4 from the absolute & put y^3 only in it:

\tt = 6x {}^{4}  |y {}^{3} |

Choice B is accurate.

7 0
1 year ago
Suppose that you randomly draw one card from a standard deck of 52 cards. After writing down which card was drawn, you replace t
34kurt

Answer:

The probability is 0.0775

The expected value is 4.75 clubs

The standard deviation is 1.8875 clubs

Step-by-step explanation:

The variable X follows a binomial distribution, because we have n identical and independent events (19 cards) with a probability p of success and 1-p of fail (there is a probability of 1/4 to be club and 3/4 to be diamond, heart or spade). Then, the probability that x of the n cards are club is:

P(x)=\frac{n!}{x!(n-x)!}*p^{x}*(1-p)^{n-x}\\P(x)=\frac{19!}{x!(19-x)!}*0.25^{x}*(0.75)^{19-x}

So, the probability P of drawing at least 8 clubs is:

P = P(8) + P(9) + P(10) + ... + P(18) + P(19)

Replacing, the values of x, from 8 to 19, on the equation above, we get:

P = 0.0775

Additionally, the expected value E(x) and standard deviationS(x) for this distribution is given by:

E(x)=np = 19(0.25) = 4.75

S(x)=\sqrt{np(1-p)} =\sqrt{19(0.25)(0.75)} =1.8875

8 0
3 years ago
Can you solve some of these? Or all, whichever one you might know. Also explain please.
Rina8888 [55]
Here's number 5. If you need more explanation just let me know.

8 0
3 years ago
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