Answer:
23°
Step-by-step explanation:
Step 1:
< GEC + < ECG + < CGE = Δ ECG Sum of a Δ
Step 2:
< IGF = < GCE Corresponding ∠ 's
Step 3:
14° + 180° - 4x + 78° = 180° Substitution
Step 4:
272° - 4x = 180° Add / Algebra
Step 5:
- 4x = - 92 Subtract 272° on both sides
Step 6:
- 92 ÷ - 4 Divide
Answer:
x = 23°
Hope This Helps :)
Carlos made the mistake that he did not combine like terms (3 x and 2 x) properly and did not use addition property of equality.
<u>Step-by-step explanation:</u>
Carlos did the work as 3 x + 2 x - 6 = 24
We need to find his mistake that he made in above given.
Here, he did not add the like terms (3 x and 2 x)
3 x + 2 x = 5 x
Therefore, his work should be
5 x - 6 = 24
Also, he did not use addition property of equality. It means the equation remains same even though the same number gets added on both sides. It would be
5 x - 6 = 24
+ 6 = + 6
-----------------------
5 x = 30
Dividing 30 by 5, we get answer as '6'. Hence,
= 6
So, stated the above two are the mistakes found in carlos work.
The answer is about 1.9166
The one with the steepest slope going down from left to right
THIS IS THE COMPLETE QUESTION BELOW
The demand equation for a product is p=90000/400+3x where p is the price (in dollars) and x is the number of units (in thousands). Find the average price p on the interval 40 ≤ x ≤ 50.
Answer
$168.27
Step by step Explanation
Given p=90000/400+3x
With the limits of 40 to 50
Then we need the integral in the form below to find the average price
1/(g-d)∫ⁿₐf(x)dx
Where n= 40 and a= 50, then if we substitute p and the limits then we integrate
1/(50-40)∫⁵⁰₄₀(90000/400+3x)
1/10∫⁵⁰₄₀(90000/400+3x)
If we perform some factorization we have
90000/(10)(3)∫3dx/(400+3x)
3000[ln400+3x]₄₀⁵⁰
Then let substitute the upper and lower limits we have
3000[ln400+3(50)]-ln[400+3(40]
30000[ln550-ln520]
3000[6.3099×6.254]
3000[0.056]
=168.27
the average price p on the interval 40 ≤ x ≤ 50 is
=$168.27
