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3 years ago

FIND BD !!!!!!!!!!!!!!!!!!!!

Mathematics

1 answer:

Viktor [21]3 years ago

4 0

BD = 2x-4

But it's also BE - CE + CD

BE is 3x-1

CE is 2x-3

CD is 2

BD = 3x-1 -(2x-3) +2

simplified

BD = 1x +4

since BD = BD (obviously), we can also say that the righthand sides of the two equation must be equal

2x -4 = 1x +4

let's solve for x and that put it into either of the 2 equations.

2x -4 = 1x +4

subtract 1x on both sides

x -4 = 4

add 4 on both sides

x = 8

substitute x for its value in 2x -4 = 1x +4

(this way we double check BD in two expressions at once. the equation should come out true, meaning same value for BD in each expression. both sides should be equal).

2*8 -4 = 1*8 +4

12 = 12

seems true

BD is safely 12

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Here's your solution

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Step-by-step explanation:

Poorly formatted question.

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