Equation at the end of step1: (7x + 18) (4) - 4x = 0 2 STEP2:Equation at the end of step 2 2 • (7x + 18) - 4x = 0 STEP3:STEP4:Pulling out like terms
4.1 Pull out like factors :
10x + 36 = 2 • (5x + 18)
Equation at the end of step4: 2 • (5x + 18) = 0 STEP5:Equations which are never true:
5.1 Solve : 2 = 0
This equation has no solution.
A a non-zero constant never equals zero.
Solving a Single Variable Equation:
5.2 Solve : 5x+18 = 0
Subtract 18 from both sides of the equation :
5x = -18
Divide both sides of the equation by 5:
x = -18/5 = -3.600
Answer: total cost = 36/w + 36/l + 9lw
Step-by-step explanation:
The formula for determining the volume of the rectangular box is expressed as
Volume = lwh
Where lwh represents the length, width and height of the box respectively.
Since the volume of the box = 3cm³,then
lwh = 3
h = 3/lw
Since the box is open, the surface area would be
2lh + 2wh + lw
Given that the material for the sides of the box costs 6 per square meter, the total cost for the sides is
(2lh × 6) + (2wh × 6)
Substituting h = 3/lw into the above expression, it becomes.
(2l × 3/lw × 6) + (2w× 3/lw × 6)
= 36/w + 36/l
Since the material for the bottom costs 9per square meter, the total cost for the bottom is
9 × lw = 9lw
Therefore, the total cost of the box as a function of the length land width is
36/w + 36/l + 9lw

<h3><u>Correct </u><u>Question </u><u>:</u><u>-</u></h3>
What is the 5th term of an AP 2 , 14 ....98 .
<h3><u>Given </u><u>:</u><u>-</u><u> </u></h3>
<u>We </u><u>have </u><u> </u><u>AP</u><u>, </u>

- <u>AP </u><u>is </u><u>the </u><u>arithmetic </u><u>progression </u><u>or </u><u>a </u><u>sequence </u><u>of </u><u>numbers </u><u>in </u><u>which </u><u>succeeding </u><u>number </u><u>is </u><u>differ </u><u>from </u><u>preceeding </u><u>number </u><u>by </u><u>a </u><u>common </u><u>value</u><u>. </u>
<h3><u>Solution </u><u>:</u><u>-</u></h3>
<u>We </u><u>have </u><u>an </u><u>AP </u><u>:</u><u>-</u><u> </u><u>2</u><u> </u><u>,</u><u> </u><u>1</u><u>4</u><u> </u><u>.</u><u>.</u><u>.</u><u>.</u><u>.</u><u>9</u><u>8</u>
<u>Therefore</u><u>, </u>
<u>Here</u><u>, </u>
Common difference of an AP



Thus, The common difference is 12
<u>Now</u><u>, </u>
We know that,





Hence, The 5th term of given AP is 50
<u>it</u><u> </u><u>is</u><u> </u><u>a</u><u> </u><u>type</u><u> </u><u>of</u><u> </u><u>trinomial</u><u> </u><u>polynomi</u><u>al</u><u> </u><u>because</u><u> </u><u>it contains </u><u>3</u><u> </u><u>terms</u><u> </u><u>with</u><u> </u><u>fundamen</u><u>tal</u><u> </u><u>signs</u><u>.</u><u> </u>
<u>hope</u><u> </u><u>it</u><u> </u><u>helps</u><u> </u><u>you</u>
Answer:
14v - 5
Step-by-step explanation:
The product of 14 and v is 14v. 5 less than that is 14v - 5.