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3 years ago

I need help with #22 & 23 ASAP!!!!please explain so I can understand

Mathematics

1 answer:

ella [17]3 years ago

5 0

Answer:

22.) y = -1/7x + 8/7 23.) y = 2x -3 (x is the slope.)

Step-by-step explanation

22.) Divided each side by 7. Subtract 1/7x from each side to get the eqaution.

23.) Divided each side by 3. Add y to each side. then subtract 9 from each side to get the equation.

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Select the number sentences that show the commutative property of addition. Mark all that apply 14+8=22

Alchen [17]

Yes 14+8 is communitive

7 0

3 years ago

The fifth graders are planning a pizza party. Each fifth grader will eat two slices of pizza with a favorite topping. One-half o

icang [17]

32 students choose a favorite topping for their slices.

Let x be the total number of students.

1/2 of the total students, or 1/2x, choose pepperoni.
1/4 of the total students, or 1/4x, choose extra cheese.
1/8 of the total students, or 1/8x, choose sausage.
4 students choose mushrooms.

We know that together, these equal the total number of students, x:
1/2x+1/4x+1/8x+4=x

We will use 8 as the common denominator:
4/8x+2/8x+1/8x+4=x

Combining like terms:
7/8x+4=x

Subtract 7/8x from both sides:
7/8x+4-7/8x=x-7/8x
4=1x-7/8x
4=1/8x

Divide both sides by 1/8:
4÷(1/8) = 1/8x÷(1/8)
4/1÷(1/8) = x
4/1×8/1 = x
32/1 = x
32 = x

4 0

3 years ago

If h(x) = 3 + 2f(x) , where f(1) = 3 and f '(1) = 4, find h'(1).

Leviafan [203]

H'(x) = 2f'(x)

h'(1) = 2*f'(1) = 2*4
h'(1) = 8

3 0

4 years ago

A box is being created out of a 15 inch by 10 inch sheet of metal. Equal-sized squares are cutout of the corners, then the sides

ivolga24 [154]

Answer:

Therefore the dimensions of the square should be 0.1528 inch by 0.1528 inch so, the box has largest volume.

Step-by-step explanation:

Given that,

A box is being created out of a 15 inches by 10 inches sheet of metal.

The length of the one side of the squares which are cut out of the each corners of the metal sheet be x.

The length of the metal box be = (15-2x) inches.

The width of the metal box be =(10-2x) inches

The height of the metal box be =x inches

Then, the volume of the metal box= length×width×height

=(15-2x)(10-2x)x cubic inches

=(150x-50x²+4x³) cubic inches

∴ V= 4x³-50x²+15x

Differentiating with respect to x

V'=12x²-100x+15

Again differentiating with respect to x

V''=24x-100

For maximum or minimum value, V'=0

12x²-100x+15=0

Apply quadratic formula $x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}$ , here a=12, b= -100 and c=15

$x=\frac{-(-100)\pm\sqrt{(-100)^2-4.12.15}}{2.12}$

$\Rightarrow x=\frac{100\pm\sqrt{9280}}{2.12}$

$\Rightarrow x=0.1528,8.18$

For x= 8.18, The value of (15-2x) and (10-2x) will negative.

∴x=0.1528 .

Now, $V''|_{x=0.1528}=24(0.1528)-100$

∴At x=0.1528 inch, the volume of the metal box will be maximum.

Therefore the dimensions of the square should be 0.1528 inch by 0.1528 inch so, the box has largest volume.

4 0

3 years ago

Consider the three points (-7,-7), (21,14), (49,35)

kykrilka [37]

E is the correct answer

6 0

4 years ago