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natka813 [3]
3 years ago
6

What is the solution of the equation when solved over the complex numbers?

Mathematics
2 answers:
marishachu [46]3 years ago
3 0

Try this option:

x²+27=0;

(x+\sqrt{-27})(x- \sqrt{-27})=0; \ => \ \left[\begin{array}{ccc}x=3 \sqrt{3}i\\x=-3 \sqrt{3}i \end{array}\right

Sonbull [250]3 years ago
3 0

x = ± 3i√3

given x² + 27 = 0 (subtract 27 from both sides )

x² = - 27 ( take the square root of both sides )

x = ±\sqrt{-27} = ± √(9 × 3 × -1 ) ← (i = √-1 )

  = ± (√9 × √3  ×√-1 ) = ±3i√3


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3 years ago
Prove the divisibility of the following numbers: 5^23−5^21 by 24
vodka [1.7K]
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6 0
4 years ago
Read 2 more answers
1. Solve the equation.
Keith_Richards [23]

Answer:

1. -3

2. -12

3. 20

4. -15

5. 6

6. -15w+5

7. 10

8. C<-26

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10. P> 16

Step-by-step explanation:

~ -9p -17 = 10

-9p = 27

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x = -12

~ p/5 +6 =10

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m = -15

~ 3n +2=8+2n

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8 0
4 years ago
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6 0
3 years ago
Read 2 more answers
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