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Minchanka [31]
3 years ago
10

Complete the two-column proof by providing a reason for each of the five statements.

Mathematics
2 answers:
snow_tiger [21]3 years ago
5 0

Answer:

A C D

Step-by-step explanation:

Mnenie [13.5K]3 years ago
4 0

Answer:

Step-by-step explanation:

Given:

RUTS is a rectangle.

To prove:

∠USR ≅ ∠SUT

                  Statements                            Reasons

1. RUTS is a rectangle                   1. Given

2. RU = ST, UT = RS                      2. By the definition of a rectangle

3. ∠STU = ∠SRU = 90°                  3. Definition of a rectangle

4. ΔURS ≅ ΔSTU                           4. By the LL theorem of congruence

5. ∠USR ≅ ∠SUT                           5. CPCTC

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Six measurements were made of the magnesium ion concentration (in parts per million, or ppm) in a city's municipal water supply,
myrzilka [38]

Answer:

163.83-4.03\frac{20.094}{\sqrt{6}}=130.77    

163.83+4.03\frac{20.094}{\sqrt{6}}=196.89    

So on this case the 99% confidence interval would be given by (130.77;196.89)    

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

Data: 175 177 175 180 138 138

We can calculate the mean and the deviation from these data with the following formulas:

\bar X= \frac{\sum_{i=1}^n x_i}{n}

s=\sqrt{\frac{\sum_{i=1}^n (x_i -\bar X)^2}{n-1}}

\bar X=163.83 represent the sample mean for the sample  

\mu population mean (variable of interest)

s=20.093 represent the sample standard deviation

n=6 represent the sample size  

The confidence interval for the mean is given by the following formula:

\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}   (1)

In order to calculate the critical value t_{\alpha/2} we need to find first the degrees of freedom, given by:

df=n-1=6-1=5

Since the Confidence is 0.99 or 99%, the value of \alpha=0.01 and \alpha/2 =0.005, and we can use excel, a calculator or a table to find the critical value. The excel command would be: "=-T.INV(0.005,5)".And we see that t_{\alpha/2}=4.03

Now we have everything in order to replace into formula (1):

163.83-4.03\frac{20.094}{\sqrt{6}}=130.77    

163.83+4.03\frac{20.094}{\sqrt{6}}=196.89    

So on this case the 99% confidence interval would be given by (130.77;196.89)    

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Simplify.<br> Rewrite the expression in the form z”. Z5 • Z6
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Answer:

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Rewrite the expression in the form z”. Z5 • Z6Simplify.

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