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larisa [96]
3 years ago
14

A school custodian waxed the gymnasium floor that measured 20 feet by 20 feet. How many square feet did she have to wax?

Mathematics
1 answer:
Irina-Kira [14]3 years ago
6 0
Hey there, all you do is multiply 20 by 20, 20×20=400. Therefore, the answer is 400 square feet.
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Can anybody check and see if 11 and 12 are correct. I will Give Brainliest Answer.
iogann1982 [59]
11 is correct, i did 12 and you did it correctly
8 0
3 years ago
The graph of a linear relation passes through the point (-2,7) and has a slope of 1/6.
docker41 [41]

Answer:

Step-by-step explanation:

eq. of any line withslope 1/6 is

y=1/6x+c

∵ it passes through (-2,7)

so 7=1/6(-2)+c

c=7+1/3=22/3

eq. of line is

y=1/6x+22/3

6 0
3 years ago
Read 2 more answers
What is the Domain of the function indicated by the points on the plane?
kondor19780726 [428]
<h2>Answer:</h2>

A.) {-6, -2, 5}

<h2>Step-by-step explanation:</h2>

A function f from a set A to a set B is a relation that assigns to each element x in the set A exactly one element y in the set B. The set A is the domain (also called the set of inputs) of the function. From the figure, we can see that this set is the x-coordinate of each red point. So this set is {-6, -2, 5}

4 0
3 years ago
Select one answer choice For part A and select one answer choice for part B
sweet [91]

\bf \qquad \qquad \qquad \textit{discriminant of a quadratic} \\\\\\ \stackrel{\stackrel{a}{\downarrow }}{1}x^2\stackrel{\stackrel{b}{\downarrow }}{+6}x\stackrel{\stackrel{c}{\downarrow }}{+9}=0 ~~~~~~~~ \stackrel{discriminant}{b^2-4ac}= \begin{cases} 0&\textit{\underline{one real solution}}~~\textit{\Large \checkmark}\\ positive&\textit{two real solutions}\\ negative&\textit{no solution} \end{cases} \\\\\\ 6^2-4(1)(9)\implies 36-36\implies 0

6 0
3 years ago
Solve triangle ABC, when A= 6, B=10 and c=12
valentinak56 [21]
Use cosine rule,

cos(A)=(b^2+c^2-a^2)/(2bc)
=(10^2+12^2-6^2)/(2*10*12)
=13/15
A=29.926 degrees.................................(A)

cos(B)=(c^2+a^2-b^2)/(2ca)
=(12^2+6^2-10^2)/(2*12*6)
=5/9
B=56.251 degrees.................................(B)

cos(C)=(a^2+b^2-c^2)/(2ab)
=(6^2+10^2-12^2)/(2*6*10)
=-1/15
C=93.823 degrees.................................(C)

Check:29.926+56.251+93.823=180.0 degrees....ok
5 0
3 years ago
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