Answer:
The laptop will not fit in the case.
Step-by-step explanation:
We need to find the width of the laptop to know if it fits in the case. We have:
<u>For the laptop</u>:
h: is the height of the laptop = 10 inch
d: is the widescreen of the laptop (diagonal) = 17 inch
w: is the width of the laptop =?
<u>For the laptop case</u>:
H: is the height of the laptop case = 10.5 inch
W: is the width of the laptop case = 13 inch
So, the width of the laptop can be found by using Pitagoras:
Hence, the laptop is 13.7 inches wide.
Therefore, since the laptop is wider than the case, the laptop will not fit in the case.
I hope it helps you!
Answer:
(c) H0 should be rejected
Step-by-step explanation:
Null hypothesis (H0): population mean is equal to 5
Alternate hypothesis (Ha): population mean is greater than 5
Z = (sample mean - population mean) ÷ (sd/√n)
sample mean = 5.3, population mean = 5, sd = 1, n = 500
Z = (5.3 - 5) ÷ (1/√500) = 0.3 ÷ 0.045 = 6.67
Using the normal distribution table, for a one tailed test at 0.01 significance level, the critical value is 2.326
Conclusion:
Since 6.67 is greater than 2.326, reject the null hypothesis (H0)
Yes, this is a perfect square because it can be square rooted to get 7x
Alright so if I do remember my math correctly, this is how it goes:
- y = -x^2 + x + 3
- x = -b/2a
- x = -1/2(-1)
- x = -1/-2, which = (1/2)
Not quite sure if this was correct, but if it was, hope this helps and you're welcome! :)
The data isn't proportional because there is a y-intercept.
20/1 is not equal to 28/2, which isnt equal to 36/3 and so on
