pls am in trouble can u help me with this question In a class of 44 boys, 22 boys play football, 20 boys play table tennis while
1 answer:
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Answer:
A) 68.33%
B) (234, 298)
Step-by-step explanation:
We have that the mean is 266 days (m) and the standard deviation is 16 days (sd), so we are asked:
A. P (250 x < 282)
P ((x1 - m) / sd < x < (x2 - m) / sd)
P ((250 - 266) / 16 < x < (282 - 266) / 16)
P (- 1 < z < 1)
P (z < 1) - P (-1 < z)
If we look in the normal distribution table we have to:
P (-1 < z) = 0.1587
P (z < 1) = 0.8413
replacing
0.8413 - 0.1587 = 0.6833
The percentage of pregnancies last between 250 and 282 days is 68.33%
B. We apply the experimental formula of 68-95-99.7
For middle 95% it is:
(m - 2 * sd, m + 2 * sd)
Thus,
m - 2 * sd <x <m + 2 * sd
we replace
266 - 2 * 16 <x <266 + 2 * 16
234 <x <298
That is, the interval would be (234, 298)
5x ÷ x² - 9 + 7 ÷ x + 3
Write the division as a fraction:
- 9 +
+ 3
Simplify the expression:
- 9 +
+ 3
Calculate the sum:
- 6 +
Write all numerators above the common denominator:
Add the numbers and you get the final answer:
Answer:
r =
Step-by-step explanation:
We simply are rearranging C= 2πr in terms of <em>r</em>. We just divide 2π on both sides.