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krok68 [10]
3 years ago
15

Part A: are they all right?

Mathematics
1 answer:
kipiarov [429]3 years ago
4 0

Answer:

yes all are corect

Step-by-step explanation:

I know becuse i did this before.

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Given ABCE is a rectangle, D is the midpoint of CE<br> Prove AD =~ BD
Bas_tet [7]

Since the congruent operator is ≅ and since AD is congruent to BD, I'm going to assume that you want to prove that AD is congruent to BD.    
1. DE is equal to CD by definition since D is the midpoint of CE.  
2. AE is equal to BC since opposite sides of a rectangle are equal to each other.  
3. Angle AEC is equal to Angle BCE since all angles in a rectangle are right angles and all right angles are equal to each other.  
4. Triangles ADE and BDC are congruent to each other because we have SAS congruence for both triangles.  
5. AD is congruent to BC since they're corresponding sides of congruent triangles.
5 0
3 years ago
Find the length of the arc and express your answer as a fraction times pie
Elina [12.6K]

Solution:

Given a circle of center, A with radius, r (AB) = 6 units

Where, the area, A, of the shaded sector, ABC, is 9π

To find the length of the arc, firstly we will find the measure of the angle subtended by the sector.

To find the area, A, of a sector, the formula is

\begin{gathered} A=\frac{\theta}{360\degree}\times\pi r^2 \\ Where\text{ r}=AB=6\text{ units} \\ A=9\pi\text{ square units} \end{gathered}

Substitute the values of the variables into the formula above to find the angle, θ, subtended by the sector.

\begin{gathered} 9\pi=\frac{\theta}{360\degree}\times\pi\times6^2 \\ Crossmultiply \\ 9\pi\times360=36\pi\times\theta \\ 3240\pi=36\pi\theta \\ Divide\text{ both sides by 36}\pi \\ \frac{3240\pi}{36\pi}=\frac{36\pi\theta}{36\pi} \\ 90\degree=\theta \\ \theta=90\degree \end{gathered}

To find the length of the arc, s, the formula is

\begin{gathered} s=\frac{\theta}{360\degree}\times2\pi r \\ Where \\ \theta=90\degree \\ r=6\text{ units} \end{gathered}

Substitute the variables into the formula to find the length of an arc, s above

\begin{gathered} s=\frac{\theta}{360}\times2\pi r \\ s=\frac{90\degree}{360\degree}\times2\times\pi\times6 \\ s=\frac{12\pi}{4}=3\pi\text{ units} \\ s=3\pi\text{ units} \end{gathered}

Hence, the length of the arc, s, is 3π units.

4 0
1 year ago
Can someone please answer this question please answer it correctly and please show work please help me I need it
vaieri [72.5K]

Answer:

A

Step-by-step explanation:

Lets find the values:

<em>Gained</em><em> </em>2.2 kg = 2.2

<em>Lost</em><em> </em>1.5 kg = (-1.5)

<em>Lost</em><em> </em>3.7 kg = (-3.7)

Adding these would be represented by the equation:

2.2 + (-1.5) + (-3.7) = ?

3 0
3 years ago
What is the area of triangle ABC to the nearest tenth of a square meter?
Andrej [43]

we are given with an isosceles triangle with two congruent sides equal to 70 inches and an angle of 36 degrees in between the sides. We are asked for the area of the triangle. The formula is A = 0.5 *  ab sin theta where  a and b are the sides. The area is equal to 1440. 07 in2. 
7 0
3 years ago
Shaded area question PLS HELP ASAp
AfilCa [17]

Answer c I’m pretty sure

Step-by-step explanation:

3 0
3 years ago
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