Using the binomial distribution, it is found that there is a 0.857 = 85.7% probability that at least 2 of the rolls come up as a 3 or a 4.
For each die, there are only two possible outcomes, either a 3 or a 4 is rolled, or it is not. The result of a roll is independent of any other roll, hence, the <em>binomial distribution</em> is used to solve this question.
Binomial probability distribution
The parameters are:
- x is the number of successes.
- n is the number of trials.
- p is the probability of a success on a single trial.
In this problem:
- There are 9 rolls, hence
.
- Of the six sides, 2 are 3 or 4, hence

The desired probability is:

In which:

Then



Then:


0.857 = 85.7% probability that at least 2 of the rolls come up as a 3 or a 4.
For more on the binomial distribution, you can check brainly.com/question/24863377
So there is this chart my teacher showed me to help find the answers to your questions I will send a picture but here are the answers
30km is 18.642m
44,000in is 111760cm
21ft is 6.401m
0.75m I’m not for sure sorry but
133yards is 121615.2mm
I hope that helps sorry I did not understand the one question 0.75m
Answer:
c. 4.27
Step-by-step explanation:
We have been given the regression equation of for predicting number of speeding tickets (Y) from information about driver age (X) as
.
To find the predicted number of tickets for a twenty-year-old, we will substitute
in our given equation.



Therefore, the predicted number of tickets for a twenty-year-old would be 4.27 tickets.
Answer :The planet Jupiter
Step-by-step explanation: It has an average distance from the sun of about
4.837
×
10
8
. The planet Venus average distance from the sun of about
6.72
×
10
7
On average, how much farther from the sun is Jupiter than Venus?