Answer:
x=42
Step-by-step explanation:
2(x-8)=68
Distribute the 2
2x-16=68
Use the addition property of equality (add 16 to both sides)
2x=68+16
2x=84
Use the division property of equality (divide both sides by 2)
x=84/2
x=42
Answer:
∠BKM= ∠ABK
Therefore AB ║KM (∵ ∠BKM= ∠ABK and lies between AB and KM and BK is the transversal line)
m∠MBK ≅ m∠BKM (Angles opposite to equal side of ΔBMK are equal)
Step-by-step explanation:
Given: BK is an angle bisector of Δ ABC. and line KM intersect BC such that, BM = MK
TO prove: KM ║AB
Now, As given in figure 1,
In Δ ABC, ∠ABK = ∠KBC (∵ BK is angle bisector)
Now in Δ BMK, ∠MBK = ∠BKM (∵ BM = MK and angles opposite to equal sides of a triangle are equal.)
Now ∵ ∠MBK = ∠BKM
and ∠ABK = ∠KBM
∴ ∠BKM= ∠ABK
Therefore AB ║KM (∵ ∠BKM= ∠ABK and BK is the transversal line)
Hence proved.
Answer:
35 ia the answer sorry if im wrong
Answer:
I know the top one is correct so the bottom has to be as well. :)
Answer:
the height of the flagpole is three fourths the height of the school. the difference in there heights is 4.5 m. what is the height of the school?
----------
Equation:
f = (3/4)s
s-f = 4.5
----
Substitute for "f" and solve for "s":
s-(3/4)s = 4.5
(1/4)s = 4.5
s = 4*4.5
s = 18 meters (height of the school)
---------------
Since f = (3/4)s, f = (3/4)(18)
= (3/2)(9)= 13.5 meters (height of the flag pole)
===============================-step explanation: HOPE THIS HELPS
