Slope: -3
y-intercept: (0,7)
<h2>Hey mate,</h2><h3>I have attached the answer below</h3><h3>Hope it will help you...</h3>
A deck has 52 cards
There were are 13 clubs
There are 4 cards with "3" but one of them is a club, so there are 3.
P (club or 3) = (13 + 3) / 52 = 4/13
The space diagonal will have length ...
... d = √(1² +4² +2²) = √(1 +16 +4) = √21
_____
This can be found using the Pythagorean theorem. A drawing can help. Find the length of any face diagonal, then use that length as the leg of a right triangle whose hypotenuse is the space diagonal and whose other leg is the edge length not used in the first calculation.
Answer:
you should accept the $1,000 bill
Step-by-step explanation:
Given the information:
- $500 for rolling 1 or 2
- $400 for rolling 3
- lose $300 for rolling 4,5,6
P (rolling 1 or 2) = 1/6 + 1/6 = 2/6 = 1/3
P (rolling a 3) = 1/6
P (rolling 4 or 5 or 6) = 3/6 = 1/2
Hence, the expected value for 1 time is:
E = (1/3)*500 + (1/6)*400 - (1/2)*300
E = $166 + $66 - $150
E = $82
Expected value is linear so if you roll the die 10 times, expected value is: 10*82 = $820
The expected value is $82, meaning you should accept the $1,000 bill
