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pychu [463]
2 years ago
7

The volume of a right circular cylinder with a base diameter of 8 in. and a height of 6 in. is ___π in3.

Mathematics
1 answer:
Arada [10]2 years ago
3 0

Answer:9

Step-by-step explanation:

This can is a right circular cylinder with a diameter of 5 inches and a height of 5 inches. What is the surface area of the can in terms of π?

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Write 600 as a product of it's primse factors
givi [52]

Answer:

2*2*2*3*5*5

or

2^3 *3* 5^2

Step-by-step explanation:

600  = 60*10

These are not prime so keep going, breaking 60 and 10 down

        = 6*10  * 5*2

6 and 10 are not prime so keep going ( 5 and 2 are prime)

    = 3*2  * 5*2  * 5*2

All of the numbers are prime, so we normally write them in order from smallest to largest

2*2*2*3*5*5

We can write with exponents

2^3 *3* 5^2

8 0
2 years ago
Find the lowest common denominator of p+3/p2+7p+10 and p5/p2+5p+6
Sunny_sXe [5.5K]
(P+1)(p+2)(p+5) is LCM
4 0
3 years ago
Read 2 more answers
Please help the questions are in the picture above
svp [43]

Not sure if I'm right but I think it's 3(x - 6) (x^2 + 5x)

Step-by-step explanation:

3x^3 - 3x^2 - 90x

Apply GCF: 3 (x^3 - x^2 - 30)

Split 30 into -6 and 5

(x^3 - 6x^2) (5x^2 - 30x)

GCF of both: x^2 (x - 6) and 5x (x - 6)

DON'T FORGET TO CARRY THE 3

And your answer is 3 (x - 6) (x^2 + 5x)

5 0
3 years ago
Is 48 a perfect cube? Explain your reasoning.
Ksivusya [100]

Answer:

No

Reasoning:

If something is a perfect cube, it is able to be put under a cube root (\sqrt[3]{..}) and will result in an integer (a non-decimal number > 0, basically).

So let's calculate \sqrt[3]{48}, and see if the result is an integer.

\sqrt[3]{48} = 3.634.......

As you can see, the result is not an integer, therefore 48 is not a perfect cube.

8 0
2 years ago
A triangle has sides of (2x), (x - 7) and (3x - 20).
LiRa [457]
2x+x-7+3x-20=87cm
6x-27=87
6x=114
x=19
Therefore the sides are:12cm, 38cm, and 37cm
7 0
3 years ago
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