V=s^3
SA=6s^2
so
125=v
125=s^3
cube root both sides
5=s
A=6(5)^2=6(25)=150 m^2
64=v
64=s^3
cube root both sides
4=s
A=6(4)^2=6(16)=96 m^2
ratio is
150:96=25:16
Jason's scores : 80 90 95 85 70 and
Jill's score : 70 75 90 100 95.
Mean of Jason's scores = 
Mean of Jill's scores = 
Now, in order to find the mean absolute deviation, need to find the difference of each score from means.
<u>Mean absolute deviation for Jason's scores.</u>
|84-80| = 4
|84-90| = 6
|84-95| = 9
|84-85| = 1
|84-70|= 14

<u>Mean absolute deviation for Jill's scores</u>
|86-70| = 16
|86-75| = 11
|86-90| = 4
|86-100| = 14
|86-95|= 9

Jill got average quiz score 86 and Jason got 84.
Therefore, Jill got better quiz average.
Also, the mean absolute deviation for Jason scores is less that is 6.8 than 10.8.
Therefore, Jason got more consistent grades.
Answer:
Hewo can anyone help
Step-by-step explanation:
I would go with the last option,it looks like it makes sense.
Hope that helped,I have snap if you need anything else :)
<em>Answer:</em>
<em>The answer to both problems is </em><em><u>GRAPH</u></em>
<em>I hope this helps:)</em>