Answer:
y'(t)=ky(t)(100-y(t))
Step-by-step explanation:
The rate of change of y(t) at any time is the derivative of y with respect to time y, y'(t)
If y(t) is the percent of the population advocating war at time t
then 100-y(t) is the percent of the population not advocating war
The product of the percentage of the population advocating war and the percentage not advocating war would be
y(t)(100-y(t))
If the rate of change of y(t) at any time is proportional to the product of the percentage of the population advocating war and the percentage not advocating war, then
y'(t)=ky(t)(100-y(t))
where <em>k is the constant of proportionality
</em>
Answer:
c) 6
Step-by-step explanation:
This is a straight-forward application of the Law of Cosines:
... a² = b² + c² -2bc·cos(A)
... a² = 8² +11² -2·8·11·cos(32.2°) ≈ 64 +121 -176·0.8462
... a² ≈ 36.07000
... a ≈ 6.00583
The best choice is c) 6.
If you take the original amount 45 and subtract the admission fee 17 you get what is left over which would be 28 dollars. Good Luck and I hope that this helps!!
Answer:
15x - 4
Step-by-step explanation:
Add both of the equations together.
f(x) + g(x)
(3x + 10x) + (2x -4)
Then, combine like terms
3x + 2x + 10x = 15x
15x - 4
Answer:
p and q, p and r, q and s
Step-by-step explanation:
hope that helps
