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Nadya [2.5K]
3 years ago
13

This is due today can anyone help ?

Mathematics
1 answer:
Lorico [155]3 years ago
7 0

Answer:

C

Step-by-step explanation:

you need to start by plugging in -2x+4 every were it says y then solve for x when you have found x plug it into one of the equations and solve for y

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Triangle OBC is a right triangle drawn on a coordinate plane. Side OC lies on the x-axis, the coordinates of point O are (0, 0),
Rudik [331]
Long leg = 8 → opposite
short leg = 6 → adjacent
hypotenuse = ?

8² + 6² = c²
64 + 36 = c²
100 = c²
√100 = √c²
10 = c

sin ∠BOC = opposite / hypotenuse
sin ∠BOC = 8 / 10 
sin ∠BOC = 0.80

tan ∠BOC = opposite / adjacent
tan ∠BOC = 8 / 6
tan ∠BOC = 1.33

3 0
3 years ago
-4x - 10x<br> Combine Like Terms
kondaur [170]

Answer:

-14x

Step-by-step explanation:

-4x+-10x =-14x

5 0
3 years ago
Read 2 more answers
Please someone help me to prove this. ​
morpeh [17]

Answer:  see proof below

<u>Step-by-step explanation:</u>

Use the Double Angle Identity: sin 2Ф = 2sinФ · cosФ

Use the Sum/Difference Identities:

sin(α + β) = sinα · cosβ + cosα · sinβ

cos(α - β) = cosα · cosβ + sinα · sinβ

Use the Unit circle to evaluate: sin45 = cos45 = √2/2

Use the Double Angle Identities:   sin2Ф = 2sinФ · cosФ

Use the Pythagorean Identity: cos²Ф + sin²Ф = 1

<u />

<u>Proof LHS → RHS</u>

LHS:                                  2sin(45 + 2A) · cos(45 - 2A)

Sum/Difference: 2 (sin45·cos2A + cos45·sin2A) (cos45·cos2A + sin45·sin2A)

Unit Circle:    2[(√2/2)cos2A + (√2/2)sin2A][(√2/2)cos2A +(√2/2)·sin2A)]  

Expand:        2[(1/2)cos²2A  + cos2A·sin2A + (1/2)sin²2A]

Distribute:              cos²2A   + 2cos2A·sin2A + sin²2A  

Pythagorean Identity:    1 + 2cos2A·sin2A

Double Angle:                1 + sin4A

LHS = RHS:  1 + sin4A = 1 + sin4A   \checkmark

6 0
3 years ago
<img src="https://tex.z-dn.net/?f=%5Csf%20%5Csqrt%7B12%7D%20%5Ctimes%20%5Csqrt%7B12%7D" id="TexFormula1" title="\sf \sqrt{12} \t
Darina [25.2K]

Answer:

12

Step-by-step explanation:

\sqrt{12} \times\sqrt{12}

\mathrm{Apply\:radical\:rule}:\quad \sqrt{a}\sqrt{a}=a,\:\quad \:a\ge 0

\sqrt{12}\sqrt{12}=12

=12

7 0
3 years ago
In care cadrane se afla graficul functiei ; f:(x)=121x
iragen [17]
<span>Solución X = {0, 121}
</span><span>espero que esto ayude</span>
8 0
3 years ago
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