Identify the property or rule shown by each equation. 9 divided 1 =9 and 33 times 1 =33

While making a book cover, Anwar uses enough material to cover the front, back, and spine of the book. He adds an extra 20 squar

Paul [167]

Your answer is 27. And your gladly welcome.

3 0

3 years ago

You have 1/8 gallon of melted crayon wax. You pour the wax equally into 8 different molds to make new crayons. What fraction of

saw5 [17]

Answer:

2 cups

Step-by-step explanation:

16/8=2 so it is 2 cups

7 0

3 years ago

5. Se hizo una encuesta a estudiantes, de una carrera de un total de 6000 estudiantes encuestados el 75% le gusta leer. ¿Cuántos

Nataly_w [17]

La encuesta indica que de entre todos los estudiantes de una carrera, 4500 les gusta leer.

<h3 /><h3>Percentage</h3>

The percentage is the given definition for a fraction whose denominator is equal to 100. It is represented by %. See the example: $\frac{30}{100} =\frac{3}{10}=0.3*100=30 \%$ .

The question gives:

6000 students
75% of students like to read

Then, you will have:

$6000\cdot \frac{75}{100}\\ \\ 6000\cdot \frac{3}{4}\\ \\ \frac{18000}{4} =4500$

Read more about the percentage here:

brainly.com/question/24304697

#SPJ1

8 0

2 years ago

If the confidence level is 90%, find the Margin of sampling error. The population is normally distributed, the sample size is 15

charle [14.2K]

Answer:

$ME = 1.761* \frac{5}{\sqrt{15}}=2.273$

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

$\bar X= 75$ represent the sample mean for the sample

$\mu$ population mean (variable of interest)

s=5 represent the sample standard deviation

n=15 represent the sample size

Solution to the problem

In order to calculate the critical value $t_{\alpha/2}$ we need to find first the degrees of freedom, given by:

$df=n-1=15-1=14$

Since the Confidence is 0.90 or 90%, the value of $\alpha=0.1$ and $\alpha/2 =0.05$ , and we can use excel, a calculator or a table to find the critical value. The excel command would be: "=-T.INV(0.05,14)".And we see that $t_{\alpha/2}=1.761$