All categories

4 years ago

Identify the property or rule shown by each equation. 9 divided 1 =9 and 33 times 1 =33

Mathematics

1 answer:

kicyunya [14]4 years ago

5 0

identity property=something times one

You might be interested in

How much space is inside the steps? (The question is attached as a picture)

julia-pushkina [17]

The pic is upside down

3 0

4 years ago

24. Ninety-four percent of NCSU transfers feel that their college adequately prepared them to handle upper-division coursework a

s2008m [1.1K]

Answer:

The answer is " $0.99999340657 \sim 1$ ".

Step-by-step explanation:

$Sucess \ probability \ (p) = 94\% \ or\ 0.94\\\\Sample\ numbers\ n = 14\\$

Using formula:

$P(X=r)= ^n C_r \times p^r \times (1-p)^{n-r}$

Let

$\to r=8,9,10,11,12,13 \ or\ 14\\\\$

Substituting the value for all r:

$P(X=8)= 0.00008540547\\\\P(X=9)= 0.00089201264\\\\P(X=10)= 0.00698743233\\\\P(X=11)= 0.03980719025\\\\P(X=12)= 0.15591149513\\\\P(X=13)= 0.37578668058\\\\P(X=14)= 0.42052319017\\$

Therefore,

$P(X>7)= P(X=8)+P(X=9)+....P(X=14)\\\\= 0.99999340657 \sim 1.$

7 0

3 years ago

Solve for x. have to turn in by tomorrow !

Mademuasel [1]

You'll do the (whole)(outside)= (whole)(outside) so, set it up like this: (5+3)3= (x+4)4now work it out with PEMDAS: 15+9=4x+16combine like terms: 24= 4x+16subtract the 16 from each side: 8=4xlastly, divide by 4 on each side to get x=2

got this from someone who answered this for me

5 0

4 years ago

Look at this graph:

Dahasolnce [82]

Answer:

20/100=1/5

Step-by-step explanation:

find the gradient of the line to find the fraction

the line is 20 units high so the line starts and stops subtracting equals 20 and the line is 100 units long to get the gradient you find the rise over the run

4 0

3 years ago

Read 2 more answers

In this problem, x = c1 cos t + c2 sin t is a two-parameter family of solutions of the second-order de x'' + x = 0. find a solut

nordsb [41]

If you are already given the general solution, finding the particular solution means to impose some conditions in order to fix the coefficients of the general solution.

The first thing we need to impose is that the function must output -1 when the input is zero. So, if we plug zero as input we have

$x(t) = c_1 \cos(t) + c_2 \sin(t) \implies x(0) = c_1 \cos(0) + c_2 \sin(0) = c_1$

But we want $x(0)=-1$ , which implies $x(0)=c_1=-1$

So, we fixed the first coefficient. To fix the second one, we can use the second piece of information (and of course the already-found value for $c_1$ ).