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charle [14.2K]
3 years ago
5

What are the domain and range of f(x)=log(x+6)-4

Mathematics
2 answers:
Gennadij [26K]3 years ago
5 0
Domain will be x + 6 > 0 -> x > -6

Range will be all real numbers, due to the range of log function
pantera1 [17]3 years ago
4 0
B.)  domain: x > -6;range: all real numbers 
XD
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What is the answer plz due today
mojhsa [17]

b would equal a + 16

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4 years ago
8x - 7x + 6 = 6 help you guys pleases
pishuonlain [190]

Steps to solve:

8x - 7x + 6 = 6

~Combine like terms

x + 6 = 6

~Subtract 6 to both sides

x = 0

Best of Luck!

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3 years ago
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Triangle DEF is to be translated left 2 units, up 4 units. What are the vertices of the translated triangle? A. D'(–1, 5), E'(3,
Leni [432]
C. D(-5,5),E(-1,2) and F(1,8)

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3 years ago
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Nady [450]
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8 0
3 years ago
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Find the angle between 4i−6j and −i 5j. (round to the nearest tenth of a degree if necessary. ) The angle between the vectors is
GarryVolchara [31]

If the vectors are 4i-6j and -i-5j then the angle between both the vectors is approximately 45°.

Given two vectors be  4i-6j and -i-5j.

We are required to find the angle between vectors  4i-6j and -i-5j.

A vector is basically an equation involving a linear combination of vctors with possibly unkown coefficients. Vector is basically a quantity that has both magnitude and direction but not possition.

Angle is basically measure of inclination of something with the surface.

The angles between two vectors can be find out by the following formula:

cos Θ=[dot product of both the vectors/(product of magnitude of both the vectors)

cos Θ=[4*(-1)+(-6)*(-5)]/\sqrt{4^{2} +(-6)^{2} } *\sqrt{(-1)^{2} +(-5)^{2} }

cos Θ=(-4+30)/\sqrt{52}\sqrt{26}

cos Θ=26/\sqrt{1352}

cos Θ=26/26.77

cos Θ=0.7070

Θ=cos^{-1}(0.707)

Θ=45.008

Approximately 45°.

Hence if the vectors are 4i-6j and -i-5j then the angle between both the vectors is approximately 45°.

Learn more about vectors at brainly.com/question/25705666

#SPJ4

3 0
2 years ago
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