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2 years ago

Students did push-ups for a fitness test. Their goal was 20 push-ups. For each student,

Mathematics

1 answer:

ale4655 [162]2 years ago

5 0

Answer:

1- 80%

2- 210%

3- 65%

4- 105%

Step-by-step explanation:

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Help!! I need to answer this question.

babunello [35]

"AC/DF = 5/2" is correct.

8 0

2 years ago

Solve sin 0 + 1 = cos20 on the interval 0 ≤ 0 < 2pi. Show work please!

yan [13]

Answer:

$\theta=\frac{\pi}{2},\frac{3\pi}{2}\frac{2\pi}{3}\frac{4\pi}{3}$

Step-by-step explanation:

You need 2 things in order to solve this equation: a trig identity sheet and a unit circle.

You will find when you look on your trig identity sheet that

$cos(2\theta)=1-2sin^2(\theta)$

so we will make that replacement, getting everything in terms of sin:

$sin(\theta)+1=1-2sin^2(\theta)$

Now we will get everything on one side of the equals sign, set it equal to 0, and solve it:

$2sin^2(\theta)+sin(\theta)=0$

We can factor out the sin(theta), since it's common in both terms:

$sin(\theta)(2sin(\theta)+1)=0$

Because of the Zero Product Property, either

$sin(\theta)=0$ or

$2sin(\theta)+1=0$

Look at the unit circle and find which values of theta have a sin ratio of 0 in the interval from 0 to 2pi. They are:

$\theta=\frac{\pi}{2},\frac{3\pi}{2}$

The next equation needs to first be solved for sin(theta):

$2sin(\theta)+1=0$ so

$2sin(\theta)=-1$ and

$sin(\theta)=-\frac{1}{2}$

Go back to your unit circle and find the values of theta where the sin is -1/2 in the interval. They are:

$\theta=\frac{2\pi}{3},\frac{4\pi}{3}$

7 0

2 years ago

Help please!!!!!!!!!!

kifflom [539]

It’s A I’m pretty sure it’s right

4 0

2 years ago

Read 2 more answers

What goes where. JdhshshHshxjancixd

valentina_108 [34]

Answer:

$\boxed { \frac{7}{5}y } \to \: \boxed {y+ \frac{2}{5}y }$

$\boxed { \frac{3}{5}y } \to \: \boxed {y - \frac{2}{5}y }$

Step-by-step explanation:

We need to simplify

$y + \frac{2}{5}y$

We collect LCM to get;

$\frac{5y + 2y}{5} = \frac{7y}{5}$

Therefore:

$\boxed { \frac{7}{5}y } \to \: \boxed {y+ \frac{2}{5}y }$

Also we need to simplify:

$y - \frac{2}{5}y$

We collect LCM to get;

$y - \frac{2}{5}y = \frac{5y - 2y}{5} = \frac{3}{5} y$

Therefore

$\boxed { \frac{3}{5}y } \to \: \boxed {y - \frac{2}{5}y }$

5 0

3 years ago

PLZ ANWSER WERTAY

kolbaska11 [484]

Answer:

-21

Step-by-step explanation:

after -22 there comes-21 so successor of-22 is -21

8 0

2 years ago