We are given two binomials: x+4 , x^2-9.
x+4 can't be factored. Therefore, it is a prime.
Let us work on x^2-9.
9 could be written as 3^2.
Therefore, x^2-9 = x^2 - 3^2.
Now, we can apply difference of the squares formula to factor it.
We know a^2 -b^2 = (a-b) (a+b).
Therefore, x^2 - 3^2 can be factored as (x-3) (x+3).
So, x^2-9 is not a prime binomial because it can be factored as (x-3) (x+3).
Answer: -216
Step-by-step explanation:
To solve the exercise you must use the formula shown below:
Where:
You should find 
The formula to find it is:
Where d is the difference between two consecutive terms.
Then:
Substitute it into the first formula. Therefore, you obtain:
Hi there!
Using the formula - n-2*180 -, we know that the interior angles of a pentagon add up to 540. We can use the values we're given and add them together and set them all equal to 540, then solve.
WORK:
540 = 204 + 12x
336 = 12x
x = 28
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