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Dahasolnce [82]
4 years ago
13

K is the midpoint of JL,JL=4x-2 and jk=7,find x KL and JL

Mathematics
1 answer:
diamong [38]4 years ago
4 0
K is the midpoint of JL...so JK=KL=7
JL=(JK + KL)>>>>>>whole part axiom
or,4x=2×JK>>>>>>>{JK=KL➡JK+KL=JK+JK}
or,4x=2×7
or,x=14/4=7/2

[ x=7/2 ] [KL=JK=7] and [JL=4x=(4×7)/2=14]
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Step-by-step explanation:

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Can you please help me with this problem
vagabundo [1.1K]
\bf \begin{cases}
\textit{area of a circle}=\pi r^2
\\ \quad \\
circumference=2\pi r
\end{cases}
\\ \quad \\

12.56=\pi r^2\implies \cfrac{12.56}{\pi }=r^2\implies \sqrt{\cfrac{12.56}{\pi }}=\boxed{r}
\\ \quad \\
thus
\\ \quad \\
circumference=2\pi \boxed{r}\implies 2\pi \boxed{\sqrt{\cfrac{12.56}{\pi }}}
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