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3 years ago

Can someone please help

Mathematics

1 answer:

pentagon [3]3 years ago

7 0

Answer:

Step-by-step explanation:

Remark

The range is the y values going from the smallest to the largest.

Y values

-3, 5,2, 0

Range

{-3,0,2,5}

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Lisa used 10 centimeters of tape to wrap 5 presents. How many presents did Lisa wrap if she used 34 centimeters of tape? Assume

3241004551 [841]

Answer:

17 presents

Step-by-step explanation:

5 presents = 10 cm tape

No. of presents = 34 cm × (5 presents/10 cm)

No. of presents = 17 presents

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2 years ago

For each part of this problem, show all your work and write a probability statement.

AlladinOne [14]

Answer:

Follows are the answer to the given point.

Step-by-step explanation:

In point 1:

$\to P( \text{number of response}) = \frac{192}{338} \\$

$= \frac{96}{169}\\\\= 0.56$

In point 2:

$\to P| \text{(Zoloft and fill response)}| = \frac{27}{338}$

$= 0.079$

In point 3:

$\to P(\frac{\text{ full or partial}}{\text{St. John's Wort}}) = \frac{\frac{43}{338}}{\frac{113}{338}}$

$= \frac{43}{338} \times \frac{338} {113}\\\\= \frac{43}{113}\\\\= 0.38$

In point 4:

$\to P(\frac{\text{Placebo}}{\text{full or response}}) = P(\frac{(\text{Placebo} \cap \text{full or response})} {\text{p(full response)}})$

$= \frac{\frac{79}{338}}{ 1- \frac{91}{338}} \\\\ = \frac{\frac{79}{338}}{ \frac{338-91}{338}} \\\\ = \frac{\frac{79}{338}}{\frac{247}{338}} \\\\ = \frac{79}{338} \times \frac {338}{247} \\\\= \frac{79}{274} \\\\ = 0.28$

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3 years ago

Find A common denominator of 1/6 and 1/9. rewrite the pair of fractions using common denominator.

Dmitry_Shevchenko [17]

The common denominators would be 2,8,6,1

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3 years ago

Select the locations on the number line to plot the points 2, 1, and −4 .

rodikova [14]

Answer:

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Step-by-step explanation:

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2 years ago

Read 2 more answers

Geometry, please answer question ASAP

Pepsi [2]

Answer:

Figures A,D are polygons.

Reason:

Polygon is a closed figure with atleast three strange lines and angles.

7 0

2 years ago

Can someone please help​

Can someone please help