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Ratling [72]
2 years ago
9

Which of the following is equal to the expression listed below?

Mathematics
2 answers:
patriot [66]2 years ago
7 0

Answer:

Step-by-step explanation:

6(4 + 3)

answer is A

Bezzdna [24]2 years ago
5 0

Answer:

first one is correct................

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Anna spent $12.25 on lunch. she wanted to leave a 20% tip for good service. how much should she leave...$0.24, $2.46, or $24.00?
vfiekz [6]
$2.46

12.25 x .20 = 2.46


5 0
3 years ago
Write this relationship as a ratio, with kilograms as units. 300 g to 5 kg. (Express your answer using a colon. Leave spaces bet
Bad White [126]

Answer:

0.3 kg : 5 kg

Step-by-step explanation:

just simplified

BRAINLIEST PLS!

8 0
2 years ago
Read 2 more answers
Use Part 1 of the Fundamental Theorem of Calculus to find the derivative of the function.
seropon [69]

Answer:

h'(x)=\frac{3r^{2}}{2\sqrt{r^3+5}}

Step-by-step explanation:

1) The Fundamental Theorem of Calculus in its first part, shows us a reciprocal relationship between Derivatives and Integration

g(x)=\int_{a}^{x}f(t)dt \:\:a\leqslant x\leqslant b

2) In this case, we'll need to find the derivative applying the chain rule. As it follows:

h(x)=\int_{a}^{x^{2}}\sqrt{5+r^{3}}\therefore h'(x)=\frac{\mathrm{d} }{\mathrm{d} x}\left (\int_{a}^{x^{2}}\sqrt{5+r^{3}}\right )\\h'(x)=\sqrt{5+r^{3}}\\Chain\:Rule:\\F'(x)=f'(g(x))*g'(x)\\h'=\sqrt{5+r^{3}}\Rightarrow h'(x)=\frac{1}{2}*(r^{3}+5)^{-\frac{1}{2}}*(3r^{2}+0)\Rightarrow h'(x)=\frac{3r^{2}}{2\sqrt{r^3+5}}

3) To test it, just integrate:

\int \frac{3r^{2}}{2\sqrt{r^3+5}}dr=\sqrt{r^{3}+5}+C

5 0
2 years ago
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