6 pt = 12 c<br> is it true or false???

What is the greatest common factor of 75 120 90?

Lilit [14]

Answer:

15 :)

Step-by-step explanation:

6 0

2 years ago

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angle K and angle L are complementary angels. If the measurement of angle K =(3x+3) and the measurement of angle L =(10x-4).what

spayn [35]

The measurement of two angles is 24° and 66°

Step-by-step explanation:

First of all, let us define complementary angles

The angles whose sum is 90° are called complementary angles

Given

∠K = (3x+3)

∠L = (10x-4)

According to the definition,

$K+L = 90\\3x+3 + 10x-4 = 90\\13x -1 = 90\\13x-1+1 = 90+1\\13x = 91$

Dividing both sides by 13

$\frac{13x}{13} = \frac{91}{13}\\x = 7$

So,

∠K = 3x + 3 = 3(7) + 3 = 21+3 = 24°

∠L = 10x - 4 = 10(7) -4 =70 -4 = 66°

Hence,

The measurement of two angles is 24° and 66°

Keywords: Complementary angles, Angles

Learn more about complementary angles at:

#LearnwithBrainly

3 0

3 years ago

A hair salon charges a fixed rate of $25.00 for a haircut and then an additional $15 for any other services. Write a function to

Taya2010 [7]

Simple,

you have a fixed rate of $25, meaning you get a haircut, it's $25

ANY other service is an extra $15

So, let's make the equation...

y=15x+25

Now, to just get a haircut it's $25.

But, let's say you get a haircut+shampoo

It'd be..

y=15(1)+25

y=$40

Another one..

You get a haircut+shampoo+highlight

y=15(3)+25

y=$70

And so on, and so forth.

3 0

3 years ago

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Find the area of a quadrilateral ABCD in which AB = 3 cm, BC = 4 cm, CD = 4 cm, DA = 5 cm and AC = 5 cm.

melamori03 [73]

Answer:

$6+2\sqrt{21}\:\mathrm{cm^2}\approx 15.17\:\mathrm{cm^2}$

Step-by-step explanation:

The quadrilateral ABCD consists of two triangles. By adding the area of the two triangles, we get the area of the entire quadrilateral.

Vertices A, B, and C form a right triangle with legs $AB=3$ , $BC=4$ , and $AC=5$ . The two legs, 3 and 4, represent the triangle's height and base, respectively.

The area of a triangle with base $b$ and height $h$ is given by $A=\frac{1}{2}bh$ . Therefore, the area of this right triangle is:

$A=\frac{1}{2}\cdot 3\cdot 4=\frac{1}{2}\cdot 12=6\:\mathrm{cm^2}$

The other triangle is a bit trickier. Triangle $\triangle ADC$ is an isosceles triangles with sides 5, 5, and 4. To find its area, we can use Heron's Formula, given by: