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3 years ago

Which of the following scenarios shows a value of 0.4? Select all that apply.

Mathematics

1 answer:

OleMash [197]3 years ago

6 0

Answer:

D and B

Step-by-step explanation:

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Explain how you would graph the line containing a slope of-1/5 that goes through the point (1,-4)

madam [21]

Answer:

y= -1/5x + 1/5

Step-by-step explanation:

y- y1 = m(x - x1)

Slope m=-1/5

(1, -4)

1 = y1

-4 = x1

y- 1 = -1/5(x-(-4))

y-1 = -1/5(x+4)

y-1= -1/5(x)+ -1/5(4)

y-1 = -1/5x + -4/5

add one to both sides

y= -1/5x + -4/5 + 1

y = -1/5x + 1/5

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4 years ago

Any two points of a circle can be joined or formed a

sergejj [24]

The answer would be Diameter
Hope this helps!

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3 years ago

Which is the value of x

vodka [1.7K]

16.5 is what I got for x you add them up and equal them to 180 because its a straight line

5 0

3 years ago

Read 2 more answers

2 divided by 3.4 divided by 5

Grace [21]

2/3.4/5

=0.1176

that is the answer

4 0

4 years ago

Read 2 more answers

Use the augmented matrix method to solve the following system of equations. Your answers may be given as decimals or fractions.

Alexandra [31]

Answer:

$x\ =\ \dfrac{21}{5}$

$y\ =\ \dfrac{3}{5}$

z = 2

Step-by-step explanation:

Given equations are

x - 2y - z = 2

x + 3y - 2z = 4

-x + 2y + 3z = 2

from the given equations the augmented matrix can be written as

$\left[\begin{array}{ccc}1&-2&-1:2\\1&3&-2:4\\-1&2&3:2\end{array}\right]$

$R_2=>R_2-R_1\ and\ R_3=>R_3+R_1$

$=\ \left[\begin{array}{ccc}1&-2&-1:2\\0&5&-1:2\\0&0&2:4\end{array}\right]$

$R_2=>\dfrac{R_2}{5}$

$=\ \left[\begin{array}{ccc}1&-2&-1:2\\0&1&\dfrac{-1}{5}:\dfrac{2}{5}\\0&0&2:4\end{array}\right]$

$R_1=>R_1+2.R_2$

$=\ \left[\begin{array}{ccc}1&0&-1-\dfrac{2}{5}:2+\dfrac{4}{5}\\\\0&1&\dfrac{-1}{5}:\dfrac{2}{5}\\\\0&0&2:4\end{array}\right]$

$=\ \left[\begin{array}{ccc}1&0&\dfrac{-7}{5}:\dfrac{14}{5}\\\\0&1&\dfrac{-1}{5}:\dfrac{2}{5}\\\\0&0&2:4\end{array}\right]$

$R_3=>\dfrac{R_3}{2}$

$=\ \left[\begin{array}{ccc}1&0&\dfrac{-7}{5}:\dfrac{14}{5}\\\\0&1&\dfrac{-1}{5}:\dfrac{2}{5}\\\\0&0&1:2\end{array}\right]$

$R_1=>R_1+\dfrac{7}{5}R_3\ and\ R_2+\dfrac{1}{5}R_3$

$=\ \left[\begin{array}{ccc}1&0&0:\dfrac{14}{5}+\dfrac{7}{5}\\\\0&1&0:\dfrac{2}{5}+\dfrac{1}{5}\\\\0&0&1:2\end{array}\right]$

So, from the above augmented matrix, we can write

$x\ =\ \dfrac{21}{5}$

$y\ =\ \dfrac{3}{5}$

z = 2

7 0

3 years ago