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IrinaK [193]
2 years ago
7

6.4n-10=4.4n+6 solve for n

Mathematics
1 answer:
Yuliya22 [10]2 years ago
5 0

Answer: n=8

Step-by-step explanation:

1. Subtract 4.4n on both sides:

2n-10=6

2. Add 10 on both sides:

2n=16

3. Divide both sides by 2:

n=8

Have a nice day :D

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The hyperbola with center at (4, 5), with vertices at (0, 5) and (8, 5), with b = 2.
galina1969 [7]
The standard form of hyperbola is:
(x-h)²/a²-(y-k)²/b²=1
center:(4,5)
Length of the horizontal transverse axis: 8-5=3=2a
thus
a=3/2
a²=9/4
b=2
b²=4

Hence the equation will be:
(x-4)²/(9/4)-(y-5)²/4=1
simplifying this we get:
[4(x-4)²]/9-(y-5)²/4=1
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A concession stand at a baseball game sells 3 apples for $2.00. How can you find the cost for 10 apples?
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In parallelogram QRST QS RT Is QRST a rectangle ?
fomenos

Answer:

The correct option is A.

Step-by-step explanation:

It is given that the QRST is a parallelogram and the diagonals QS and RT are congruent.

According to the property of parallelogram if the length of diagonals are same, then the parallelogram is rectangle. We can also prove it.

Let QRST be an parallelogram and QS=RT.

In triangles QRT and RQS.

RT=QS         (Diagonals)

QR=QR         (Common side)

QT=RS         (Opposite sides of the parallelogram are same)

So by SSS rule of congruence, triangle QRT and triangle RQS are congruent.

By CPCT,

\angle R=\angle Q

Since the sum of two consecutive angles of a parallelogram is 180 degree.

\angle R+\angle Q=180

2\angle R=180

\angle R=90

Therefore the measure of angle R and angle Q are 90 degree.

Similarly in triangle QST and RTS,

RT=QS         (Diagonals)

ST=ST         (Common side)

QT=RS         (Opposite sides of the parallelogram are same)

So by SSS rule of congruence, triangle QST and RTS are congruent.

By CPCT,

\angle S=\angle T

Since the sum of two consecutive angles of a parallelogram is 180 degree.

Therefore the measure of angle S and angle T are 90 degree.

Since the measure of all interior angles of QRST are 90 degree, therefore the parallelogram QRST  is a rectangle.

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