Answer:
Step-by-step explanation:
we know that
The surface area of the regular pyramid is equal to the area of the triangular base plus the area of its three triangular lateral faces
step 1
Find the area of the triangular base
we know that
The triangular base is an equilateral triangle
so
The area applying the law of sines is equal to
step 2
Find the area of its three triangular lateral faces
![A=3[\frac{1}{2}bh]](https://tex.z-dn.net/?f=A%3D3%5B%5Cfrac%7B1%7D%7B2%7Dbh%5D)
we have
Find the height of triangles
Applying the Pythagorean Theorem
solve for h
substitute
![A=3[\frac{1}{2}(14)\sqrt{51}]](https://tex.z-dn.net/?f=A%3D3%5B%5Cfrac%7B1%7D%7B2%7D%2814%29%5Csqrt%7B51%7D%5D)
step 3
Find the surface area
Adds the areas
Round to the nearest tenth
Answer:
90
Step-by-step explanation:
First, we should find the area of the trapezoid, and then subtract the area of the removed triangle in order to find the shaded area.
Area of the trapezoid
1) Area of the rectangle in the middle.
Base Length: 10
Height Length: 10
Area: 10 x 10 = 100
2. Area of the triangles on the side
Base Length: (14 - 10)/2 = 2
Height Length: 10
Area: 2 x 10 x 1/2 = 10
There are two triangles: 10 x 2 = 20
Area of the trapazoid: 100 + 20 = 120
Area of the triangle that's been removed
Base Length: 10
Height Length: 10 - 4 = 6
Area: 10 x 6 x 1/2 = 30
Shaded area
Area of the trapezoid - Area of the triangle
120 - 30 = 90
Area of the shaded region is 90.
Answer:
p: (-4)2 > 0
q: An isosceles triangle has two congruent sides.
r: Two angles, whose measure have a sum of 90, are supplements.
Step-by-step explanation:
p: (-4)2 > 0
q: An isosceles triangle has two congruent sides.
r: Two angles, whose measure have a sum of 90, are supplements.
Answer:
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Step-by-step explanation:
