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3 years ago

1. What is the y-intercept in the table below?

Mathematics

1 answer:

11Alexandr11 [23.1K]3 years ago

5 0

Answer:

EWAN KO DYA DI AKO MATH EXPERT

Step-by-step explanation:

POIU

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Find the value of n×8 when n =6<br><br> ×- 6y

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Answer:

6x8 is a easy multiplication problem that equals 48

Step-by-step explanation:

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3 years ago

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What is the graph of the inequality in the coordinate plane?<br><br> x ≥ 4

34kurt

If the solution is gray area, then neither of these graphs is a solution.

If the solution is white area, then the second graph from the left is a solution.

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3 years ago

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If EFH = (5x + 1)°, HFG = 62°, and EFG = (18x + 11)°, find EFH

olga55 [171]

Given:

Consider the below figure attached with this question.

∠EFH = (5x + 1)°, ∠HFG = 62°, and ∠EFG = (18x + 11)°

To find:

The measure of ∠EFH.

Solution:

From the figure it is clear that ∠EFG is divide in two parts ∠EFH and ∠HFG. So,

$\angle EFG=\angle EFH+\angle HFG$

$18x+11=(5x+1)+(62)$

$18x+11=5x+63$

Isolate variable terms.

$18x-5x=63-11$

$13x=52$

Divide both sides by 13.

$x=\dfrac{52}{13}$

$x=4$

The value of x is 4.

$\angle EFH=(5x+1)^\circ$

$\angle EFH=(5(4)+1)^\circ$

$\angle EFH=(20+1)^\circ$

$\angle EFH=21^\circ$

Therefore, the measure of ∠EFH is 21°.

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3 years ago

A bag of turf builder sun and shade mix grass seed covers an area of 4000ft.How many bags are needed to cover an area of 35,000f

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Answer: you will get 8.75, but the answer should be 9 bags

Step-by-step explanation:

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3 years ago

NO LINKS!! What is the equation shown in the smaller circle shown in the figure?

konstantin123 [22]

${\qquad\qquad\huge\underline{{\sf Answer}}}$

Here we go ~

The general equation of ellipse is :

$\qquad \sf \dashrightarrow \: \cfrac{ {x}^{2} }{ {a}^{2} } + \cfrac{ {y}^{2} }{ {b}^{2} } = 1$

[ because it's a horizontal ellipse with centre at origin ]

so, let's equate given equation with the standard equation ~

$\qquad \sf \dashrightarrow \: \cfrac{ {x}^{2} }{64} + \cfrac{ {y}^{2} }{36} = 1$

se get :

a² = 64 ; a = 8

b² = 36 ; b = 6

As we know, length of minor axis is : 2b = 2 × 6 = 12 units

and, the smaller circle has diameter = 2b = 12 units

so, it's radius = 6 units ~

Now, let's write the equation of circle with origin as centre and radius = 6 units

$\qquad \sf \dashrightarrow \: {(x - h)}^{2} + (y - k) {}^{2} = {r}^{2}$

[ h = 0, k = 0, since circle has centre at origin ]

$\qquad \sf \dashrightarrow \: {x}^{2} + {y}^{2} = 36$

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