I don't understand what you mean but this might be the answer
Can you please give me brainiest :D
Answer:
Step-by-step explanation:
<u>Since all graphs pass throught the origin, they all have the form of:</u>
- y = ax², where a- coefficient
The coefficient of each graph's equation can be calculated based on the given pairs of points.
Each of them calculated for you and attached below.
Answer:
The answer to the question are
(B) The set is not a vector space because it is not closed under addition. and
(D) The set is not a vector space because an additive inverse does not exist.
Step-by-step explanation:
To be able to identify the possible things that can affect a possible vector space one would have to practice on several exercises.
The vector space axioms that failed are as follows
(B) The set is not a vector space because it is not closed under addition.
(2·x⁸ + 3·x) + (-2·x⁸ +x) = 4·x which is not an eighth degree polynomial
(D) The set is not a vector space because an additive inverse does not exist.
There is no eight degree polynomial = 0
The axioms for real vector space are
- Addition: Possibility of forming the sum x+y which is in X from elements x and y which are also in X
- Inverse: Possibility of forming an inverse -x which is in X from an element x which is in X
- Scalar multiplication: The possibility of forming multiplication between an element x in X and a real number c of which the product cx is also an element of X
