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2 years ago

10

Joey is building a doghouse. He measures the lengths of two sides and the hypotenuse to make sure the boards create a right tria

ngle.
Which of the measurements below could be used to create the right triangle?

5 in, 7 in, 12 in
8 in, 12 in 14 in
5 in, 9 in, 11 in
6 in, 8 in, 10 in
pleasee help mee

1 answer:

svetlana [45]2 years ago

7 0

Answer: 6in, 8in, 10in

6 squared + 8 squared equals to the radical of 100, which equals to 10 because 10 squared is.. 100

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If the discriminant of a quadratic equation is equal to -8, which statement describes the roots?

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Step-by-step explanation:

we know that

In a quadratic equation of the form $ax^{2} +bx+c=0$

The discriminant is equal to $b^{2} -4ac$

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3 years ago

What is the area,in the square units,of the rectangle?

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2 years ago

jolli1 [7]

Answer:

Part 1) $r=3.5\%$

Part 2) $t=6\ years$

Part 3) $21.9\ ft$

Step-by-step explanation:

Part 1) we know that

The formula to calculate continuously compounded interest is equal to

$A=P(e)^{rt}$

where

A is the Final Investment Value

P is the Principal amount of money to be invested

r is the rate of interest in decimal

t is Number of Time Periods

e is the mathematical constant number

Let

x -----> amount of money to be invested

2x ---> Final Investment Value

we have

$t=20\ years\\ P=\$x\\A=\$2x\\r=?$

substitute in the formula above

$2x=x(e)^{20r}$

$2=(e)^{20r}$

Apply ln both sides

$ln(2)=ln[(e)^{20r}]$

$ln(2)=(20r)ln(e)$

$ln(2)=(20r)$

$0.693=(20r)$

$r=0.693/20$

$r=0.035$

$r=3.5\%$

Part 2) we know that

The formula to calculate continuously compounded interest is equal to

$A=P(e)^{rt}$

where

A is the Final Investment Value

P is the Principal amount of money to be invested

r is the rate of interest in decimal

t is Number of Time Periods

e is the mathematical constant number

Let

x -----> amount of money to be invested

2x ---> Final Investment Value

we have

$t=?\ years\\ P=\$x\\A=\$2x\\r=0.126$

substitute in the formula above

$2x=x(e)^{0.126t}$

$2=(e)^{0.126t}$

Apply ln both sides

$ln(2)=ln[(e)^{0.126t}]$

$ln(2)=(0.126t)ln(e)$

$ln(2)=(0.126t)$

$0.693=(0.126t)$

$t=0.693/0.126$

$t=5.5=6\ years$

Part 3) we have

$f(x)=18.4+2.5ln(x+1)$

where

f(x) -----> is the long jump record in feet

x -----> the number of years since the school was opened

so

For x=3 years

substitute

$f(3)=18.4+2.5ln(3+1)$

$f(3)=18.4+2.5ln(4)$

$f(3)=18.4+2.5(1.386)$

$f(3)=21.9\ ft$

4 0

3 years ago