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Assoli18 [71]
3 years ago
6

Which of the following is an irrational number

Mathematics
2 answers:
kondaur [170]3 years ago
6 0

Answer:

D) any number that isn't a perfect square is irrational

Step-by-step explanation:

disa [49]3 years ago
3 0

Answer:

D                              PLEASE MARK BRANLIEST

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Two cyclists leave city at same time, one going east and the other going west. The westbound cyclist bikes 3 mph faster than the
Bumek [7]

Speed of the east bound cyclist is 12 mph and the speed of west bound cyclist is 15 mph.

<u>Solution:</u>

Let us assume that x is speed of slower eastbound cyclist

So, x+3 will be the speed of faster westbound cyclist

We know that distance is the product of speed and time. That is,

\text{Distance}=\text{Speed}\times\text{Time}

West-bound DATA:

Rate of speed = x+3 mph ; Time = 6 hrs ; distance = 6(x+3) = 6x+18 miles

East-bound DATA:

Rate of speed = x mph ; time = 6 hrs. ; distance = 6x miles

On solving,

Distance apart = 162

\Rightarrow6x+18+6x = 162

\Rightarrow12x=162-18

\Rightarrow x=\frac{144}{12}\rightarrow x=12

So, the rate of speed of the east bound cyclist is 12 mph and the rate of speed of the west bound cyclist will be x+3=12+3=15 \text{ mph}

8 0
3 years ago
Find the inverse of the given​ matrix, if it exists.Aequals=left bracket Start 3 By 3 Matrix 1st Row 1st Column 1 2nd Column 0 3
BabaBlast [244]

Answer:

A^{-1}=\left[ \begin{array}{ccc} \frac{1}{9} & \frac{4}{27} & - \frac{2}{27} \\\\ \frac{8}{9} & \frac{5}{27} & \frac{11}{27} \\\\ - \frac{4}{9} & \frac{2}{27} & - \frac{1}{27} \end{array} \right]

Step-by-step explanation:

We want to find the inverse of A=\left[ \begin{array}{ccc} 1 & 0 & -2 \\\\ 4 & 1 & 3 \\\\ -4 & 2 & 3 \end{array} \right]

To find the inverse matrix, augment it with the identity matrix and perform row operations trying to make the identity matrix to the left. Then to the right will be inverse matrix.

So, augment the matrix with identity matrix:

\left[ \begin{array}{ccc|ccc}1&0&-2&1&0&0 \\\\ 4&1&3&0&1&0 \\\\ -4&2&3&0&0&1\end{array}\right]

  • Subtract row 1 multiplied by 4 from row 2

\left[ \begin{array}{ccc|ccc}1&0&-2&1&0&0 \\\\ 0&1&11&-4&1&0 \\\\ -4&2&3&0&0&1\end{array}\right]

  • Add row 1 multiplied by 4 to row 3

\left[ \begin{array}{ccc|ccc}1&0&-2&1&0&0 \\\\ 0&1&11&-4&1&0 \\\\ 0&2&-5&4&0&1\end{array}\right]

  • Subtract row 2 multiplied by 2 from row 3

\left[ \begin{array}{ccc|ccc}1&0&-2&1&0&0 \\\\ 0&1&11&-4&1&0 \\\\ 0&0&-27&12&-2&1\end{array}\right]

  • Divide row 3 by −27

\left[ \begin{array}{ccc|ccc}1&0&-2&1&0&0 \\\\ 0&1&11&-4&1&0 \\\\ 0&0&1&- \frac{4}{9}&\frac{2}{27}&- \frac{1}{27}\end{array}\right]

  • Add row 3 multiplied by 2 to row 1

\left[ \begin{array}{ccc|ccc}1&0&0&\frac{1}{9}&\frac{4}{27}&- \frac{2}{27} \\\\ 0&1&11&-4&1&0 \\\\ 0&0&1&- \frac{4}{9}&\frac{2}{27}&- \frac{1}{27}\end{array}\right]

  • Subtract row 3 multiplied by 11 from row 2

\left[ \begin{array}{ccc|ccc}1&0&0&\frac{1}{9}&\frac{4}{27}&- \frac{2}{27} \\\\ 0&1&0&\frac{8}{9}&\frac{5}{27}&\frac{11}{27} \\\\ 0&0&1&- \frac{4}{9}&\frac{2}{27}&- \frac{1}{27}\end{array}\right]

As can be seen, we have obtained the identity matrix to the left. So, we are done.

6 0
3 years ago
It takes Gaby only a few hours to read a long book. Which is the dependent variable in this situation?
slamgirl [31]
I believe it is C, but correct me if I'm wrong.
4 0
3 years ago
Read 2 more answers
The number of hours per week that the television is turned on is determined for each family in a sample. the mean of the data is
nikdorinn [45]
Not sure on the number listed as median ? 27.227.2? Please clarify.
5 0
3 years ago
<img src="https://tex.z-dn.net/?f=%5Cfrac%7B33%7D%7B4-%5Csqrt%7B5%7D%20%7D" id="TexFormula1" title="\frac{33}{4-\sqrt{5} }" alt=
kvv77 [185]
The answer I got was: 12 + 3/5

Sorry I didn’t have that symbol thing on my phone so i had to use a slash.
Hope this helps :)
7 0
3 years ago
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