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schepotkina [342]
3 years ago
8

Solve for x in the equation x^2 -10+25=35?

Mathematics
1 answer:
sineoko [7]3 years ago
5 0

Answer:

5\frac{+}{-} \sqrt{35}

Let's solve your equation step-by-step.

x^2−10+25=35

Step 1: Simplify both sides of the equation.

x^2+15=35

Step 2: Subtract 15 from both sides.

x^2+15−15=35−15

x^2=20

Step 3: Take square root.

x=±√20

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I'm not sure how to answer this question. Could someone please help explain it?
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Consider the parent function, \displaystyle{ f(x)= \sqrt{x}. 

The function f, takes a number x, and produces the square root of it, for example we have the points:

(1, 1), (4, 2), (25, 5), (100, 10).


The function \displaystyle{ g(x)= \sqrt{x-5}, takes a value x, subtracts it 5, and then produces the square root of this difference.


So to produce the values 1, 2, 5, 10 given in the previous function, we need to 

plug in the function not 1, 4, 25, and 100, but 6, 9, 30, 105.


Comparing  : (1, 1), (4, 2), (25, 5), (100, 10) of (x, f(x)) with 

                      (6, 1), (9, 2), (30, 5), (105, 10) of (x, g(x)),

we see that the graph of g is the same as the graph of f shifted 5 units right.



In general, the graph of  y=f(x-a), where a is a positive number, is the graph of y=f(x) shifted a units right.  

Answer: C
3 0
4 years ago
Find the area of the given figure.<br> (answer choices on pictures)
Sergio039 [100]

Answer:

C) 63.2 cm^2

Step-by-step explanation:

Square: (b)(h) = 6 cm x 7.2 cm = 43.2^2

Subtract 10 from 6 to get the width of the rectangle.

Rectangle: (b)(h) = 4 x 2.8 = 11.2 cm^2

To find the triangle, subtract 7.2 with 2.8 and subtract 10 with 6.

Triangle: (1/2)(b)(h) = (1/2)(4)(4.4) = (1/2)(17.6) = 8.8 cm^2

Now, add everything together.

43.2 + 11.2 + 8.8 = 63.2 cm^2

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3 years ago
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Alexandra [31]

Hello there!

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8 0
3 years ago
GEOMETRY QUESTION, HELP PLEASEEE.
choli [55]

Answer:

The pre-image C is (2, 5)

Step-by-step explanation:

  • If the point (x, y) rotated about the origin by angle 90° clockwise, then its image is (y, -x)
  • If the point (x, y) rotated about the origin by angle 180° clockwise, then its image is (-x, -y)
  • If the point (x, y) rotated about the origin by angle 270° clockwise, then its image is (-y, x)

∵ Point C was rotated 270° clockwise around the origin

∵ C' = (-5, 2)

→ By using the 3rd rule above

∵ The image of the point (x, y) is (-y, x)

∴ (-y, x) = (-5, 2)

→ That means -y = -5 and x = 2

∴ x = 2

∴ -y = -5

→ Divide both sides by -1

∴ y = 5

∴ The pre-image C = (2, 5)

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Step-by-step explanation:

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