Answer:
x = 8
x = 21/14
x = 8
x = 15/21
x = 1/4
x = 7
Step-by-step explanation:
(For all instances of number, let it be x)
Double the sum of a number and 15. The result is the same as the product of 23 and the number.
2x + 15 = 23 + x
2x - x + 15 = 23 + x - x
x + 15 = 23
x + 15 - 15 = 23 - 15
x = 8
Multiply a number by 15 and add 2. The result is the same as the sum of 23 and the number.
15x + 2 = 23 + x
14x + 2 = 23
14x = 21
x = 21/14
Double a number and add 15. The result is the same as the sum of 23 and the number.
2x + 15 = 23 + x
x + 15 = 23
x = 8
Double a number and add 15. The result is the same as the product of 23 and the number. (This time we will move the x to the other side as the right side has a larger x than the left side)
2x + 15 = 23x
15 = 21x
x = 15/21
Multiply a number by 15 and add 2. The result is the same as the product of 23 and the number.
15x + 2 = 23x
2 = 8x
2/8 = x
x = 1/4
Double the sum of a number and 15. The result is the same as the sum of 23 and the number.
2(x + 15) = 23 + x
2x + 30 = 23 + x
x + 30 = 23
x = 7
Hello!
6.
Since the area is that of a square, you know that all side lengths are the same.
Area is base times height (A = bh), but since base and height are the same for a square, you get the formula A = a².




The length of the side of a square with an area of 144 in² is
12 in.
7.
Rational number.
8.
This is a right triangle; use the Pythagorean Theorem to find missing lengths of right triangles. Pythagorean Theorem: a² + b² = c², where c is the hypotenuse of the triangle.
Plug in your leg lengths:
a² + b² = c²
8² + x² = 21²
64 + x² = 441
x² = 377
x = 19.4
3 1/2 or 7/2
keep the 3 yards and round the 4/5 to half a yard or 1/2 and just in case turn into a improper fraction
Answer:
102 mg
Step-by-step explanation:
Let's convert 28 pounds to kgs.
Since 1 kg = 2.2 pounds, we can find:

So 28 pounds is 12.73 Kg
Since 8mg is given per kg, for 12.73 kg, the amount given should be:
12.73 * 8 = 101.84
Rounded to nearest whole number, that is, 102 mg
A. Hope this helps (give brainliest)