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taurus [48]
3 years ago
8

What is the slope for 3y+6x=9

Mathematics
1 answer:
Ivenika [448]3 years ago
7 0

Answer:

The slope is -2!

Step-by-step explanation:

Lets Solve!

3y +6x = 9

First we subtract 6x from both sides

3y = -6x + 9

Next we divide by 3 from both sides.

y = -2x + 3

The slope is -2!

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10(g+5)=2(g+9). <br> please help
MAVERICK [17]

Answer:

g=-4

Step-by-step explanation:

7 0
2 years ago
I'LL GIVE BRAINLIEST
Nutka1998 [239]

Answer:

Exact form: v=80/13

Nearest tenth: 6.2

Step-by-step explanation:

Hope it helps!

8 0
3 years ago
The time for a professor to grade an exam is normally distributed with a mean of 16.3 minutes and a standard deviation of 4.2 mi
dem82 [27]

Answer:

62.17% probability that a randomly selected exam will require more than 15 minutes to grade

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

\mu = 16.3, \sigma = 4.2

What is the probability that a randomly selected exam will require more than 15 minutes to grade

This is 1 subtracted by the pvalue of Z when X = 15. So

Z = \frac{X - \mu}{\sigma}

Z = \frac{15 - 16.3}{4.2}

Z = -0.31

Z = -0.31 has a pvalue of 0.3783.

1 - 0.3783 = 0.6217

62.17% probability that a randomly selected exam will require more than 15 minutes to grade

8 0
3 years ago
Please help me out guys. The photo will show you what to do. 50 points cause I need it done fast
Nonamiya [84]

Answer:

a) starting height: 5.5 ft

b) hang time: 5.562 seconds

c) maximum height: 126.5 ft

d) time to maximum height: 2.75 seconds

Step-by-step explanation:

a) The starting height is the height at t=0.

h(0) = -16·0 +88·0 +5.5

h(0) = 5.5

The starting height is 5.5 feet.

__

b) The ball is in the air between t=0 and the non-zero time when h(t) = 0. We can find the latter by solving ...

-16t^2 + 8t +5.5 = 0

t^2 -(11/2)t = 5.5/16 . . . . . subtract 5.5, then divide by -16

t^2 -(11/2)t +(11/4)^2 = (5.5/16) +(11/4)^2 . . . . complete the square

(t -11/4)^2 = 126.5/16 . . . . . . . . . . . . . . . . . . . . call this [eq1] for later use

t -11/4 = √7.90625

t = 2.75 +√7.90625 ≈ 5.562

The ball will be in the air about 5.562 seconds.

__

c) If we multiply [eq1] above by -16 and add the constant on the right, we get the vertex form of the height equation:

h(t) = -16(t -11/4) +126.5

The vertex at (2.75, 126.5) tells us ...

The maximum height of the ball is 126.5 feet.

__

d) That same vertex point tells us ...

The maximum height will be reached at t = 2.75 seconds.

_____

If you really need answers fast, a graphing calculator can give them to you in very short order (less than a minute).

6 0
3 years ago
An insecticible contains 85 centigrams of inert ingredient for every 1 centigram of active ingredient. if a quantity of the weig
11111nata11111 [884]
(85/86)*688 cg = 680 cg . . . inert ingredient
.. 688 cg -680 cg = 8 cg . . . .active ingredient
7 0
3 years ago
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